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3.6gm of a gas at 27′degree celsius occupied the same volume as 0.18gm of hydrogen at 27 degree celsius and at the same pressure. The molecular weight of gas is?
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3.6gm of a gas at 27′degree celsius occupied the same volume as 0.18gm...
< b="" />Given data:< />
- Mass of gas = 3.6 g
- Mass of hydrogen = 0.18 g
- Temperature = 27°C
- Pressure is the same for both gases
< b="" />Calculations:< />
< b="" />1. Calculate the number of moles of each gas:< />
- Number of moles of gas = mass of gas / molar mass of gas
- Number of moles of hydrogen = mass of hydrogen / molar mass of hydrogen
< b="" />2. Since the volume, temperature, and pressure are the same for both gases, they must have the same number of moles:< />
- Number of moles of gas = Number of moles of hydrogen
- Mass of gas / molar mass of gas = mass of hydrogen / molar mass of hydrogen
< b="" />3. Calculate the molecular weight of the gas:< />
- From the above equation, we can find the molar mass of the gas.
< b="" />4. Substitute the given values and solve for the molecular weight:< />
- molar mass of gas = (mass of gas * molar mass of hydrogen) / mass of hydrogen
< b="" />5. Find the molecular weight of the gas:< />
- Substitute the given values and calculate the molecular weight of the gas.
Therefore, by following the above steps, you can determine the molecular weight of the gas using the given data and the principles of ideal gas behavior.
Community Answer
3.6gm of a gas at 27′degree celsius occupied the same volume as 0.18gm...
40 g mol^-1
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3.6gm of a gas at 27′degree celsius occupied the same volume as 0.18gm of hydrogen at 27 degree celsius and at the same pressure. The molecular weight of gas is?
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