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The sum of the numerator and the denominator of a fraction is 67. When 31 is added to the denominator, the fraction becomes 3 / 11. What was the original fraction?
  • a)
    21/ 36
  • b)
    12 / 46
  • c)
    21 / 46
  • d)
    12 / 36
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The sum of the numerator and the denominator of a fraction is 67. When...
To solve this problem, we need to set up a system of equations based on the given information.

Let's assume the original fraction is a/b, where a is the numerator and b is the denominator.

1. The sum of the numerator and the denominator is 67.
a + b = 67

2. When 31 is added to the denominator, the fraction becomes 3/11.
a / (b + 31) = 3/11

Now we can solve these equations.

1. Rearrange the first equation to express a in terms of b:
a = 67 - b

2. Substitute this expression for a in the second equation:
(67 - b) / (b + 31) = 3/11

3. Cross-multiply to get rid of the fractions:
11(67 - b) = 3(b + 31)

4. Expand and simplify:
737 - 11b = 3b + 93

5. Move all the b terms to one side and the constant terms to the other side:
737 - 93 = 3b + 11b
644 = 14b

6. Divide both sides by 14 to solve for b:
b = 644 / 14
b = 46

Now that we have the value of b, we can substitute it back into the first equation to solve for a:

a + 46 = 67
a = 67 - 46
a = 21

Therefore, the original fraction is 21/46, which matches option C.
Free Test
Community Answer
The sum of the numerator and the denominator of a fraction is 67. When...
Numerator + Denominator = 67
After adding 31 to the denominator, the numerator is 3 units and denominator is 11 units.
3 + 11 = 14 units = 67 + 31 = 98
∴ 1 unit = 98 ÷ 14 = 7
3 units = 3 × 7 = 21 and 11 units = 11 × 7 = 77
New fraction = 21 / 77
Hence, the original fraction
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The sum of the numerator and the denominator of a fraction is 67. When 31 is added to the denominator, the fraction becomes 3 / 11. What was the original fraction?a)21/ 36b)12 / 46c)21 / 46d)12 / 36Correct answer is option 'C'. Can you explain this answer?
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