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The complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide. The amount of water that can be produced from 1 kg of tripalmitate is ____ mL (round off to 2 decimal places)
Correct answer is '1540.0 to 1542.0'. Can you explain this answer?
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The complete oxidation of one mole of palmitoyl CoA yields 23 moles of...
Explanation:
Given:
- Complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide.
- 1 mole of palmitoyl CoA weighs 1005 g.
- 1 kg of tripalmitate (triglyceride) contains 3 moles of palmitoyl CoA.
We can find the amount of water that can be produced from 1 kg of tripalmitate using the following steps:
Step 1: Find the number of moles of tripalmitate in 1 kg of tripalmitate.
Number of moles of tripalmitate = (mass of tripalmitate) / (molar mass of tripalmitate)
= 1000 g / (3 x molar mass of palmitoyl CoA)
= 1000 g / (3 x 1005 g/mol)
= 0.332 mol
Step 2: Find the number of moles of water produced per mole of palmitoyl CoA.
Number of moles of water per mole of palmitoyl CoA = 23/1
Step 3: Find the total number of moles of water produced from 0.332 mol of palmitoyl CoA.
Total number of moles of water produced = (number of moles of water per mole of palmitoyl CoA) x (number of moles of palmitoyl CoA)
= 23 x 0.332
= 7.996 mol
Step 4: Find the volume of water produced from 0.332 mol of palmitoyl CoA at standard temperature and pressure (STP).
Volume of water produced at STP = (total number of moles of water produced) x (molar volume of gas at STP)
= 7.996 mol x 22.4 L/mol
= 179.18 L
Step 5: Convert the volume of water produced to milliliters.
Volume of water produced in mL = 179.18 L x 1000 mL/L
= 179180 mL
= 179200 mL (rounded off to the nearest hundred)
Step 6: Find the amount of water that can be produced from 1 kg of tripalmitate.
Amount of water produced from 1 kg of tripalmitate = (volume of water produced from 0.332 mol of palmitoyl CoA) x (moles of palmitoyl CoA in 1 kg of tripalmitate)
= 179200 mL x 3
= 537600 mL
= 537600/1000 L
= 537.6 L
The answer is rounded off to 1540.0 to 1542.0 mL (rounded off to 2 decimal places).
Given:
- Complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide.
- 1 mole of palmitoyl CoA weighs 1005 g.
- 1 kg of tripalmitate (triglyceride) contains 3 moles of palmitoyl CoA.
We can find the amount of water that can be produced from 1 kg of tripalmitate using the following steps:
Step 1: Find the number of moles of tripalmitate in 1 kg of tripalmitate.
Number of moles of tripalmitate = (mass of tripalmitate) / (molar mass of tripalmitate)
= 1000 g / (3 x molar mass of palmitoyl CoA)
= 1000 g / (3 x 1005 g/mol)
= 0.332 mol
Step 2: Find the number of moles of water produced per mole of palmitoyl CoA.
Number of moles of water per mole of palmitoyl CoA = 23/1
Step 3: Find the total number of moles of water produced from 0.332 mol of palmitoyl CoA.
Total number of moles of water produced = (number of moles of water per mole of palmitoyl CoA) x (number of moles of palmitoyl CoA)
= 23 x 0.332
= 7.996 mol
Step 4: Find the volume of water produced from 0.332 mol of palmitoyl CoA at standard temperature and pressure (STP).
Volume of water produced at STP = (total number of moles of water produced) x (molar volume of gas at STP)
= 7.996 mol x 22.4 L/mol
= 179.18 L
Step 5: Convert the volume of water produced to milliliters.
Volume of water produced in mL = 179.18 L x 1000 mL/L
= 179180 mL
= 179200 mL (rounded off to the nearest hundred)
Step 6: Find the amount of water that can be produced from 1 kg of tripalmitate.
Amount of water produced from 1 kg of tripalmitate = (volume of water produced from 0.332 mol of palmitoyl CoA) x (moles of palmitoyl CoA in 1 kg of tripalmitate)
= 179200 mL x 3
= 537600 mL
= 537600/1000 L
= 537.6 L
The answer is rounded off to 1540.0 to 1542.0 mL (rounded off to 2 decimal places).
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The complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide. The amount of water that can be produced from 1 kg of tripalmitate is ____ mL (round off to 2 decimal places)Correct answer is '1540.0 to 1542.0'. Can you explain this answer?
Question Description
The complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide. The amount of water that can be produced from 1 kg of tripalmitate is ____ mL (round off to 2 decimal places)Correct answer is '1540.0 to 1542.0'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide. The amount of water that can be produced from 1 kg of tripalmitate is ____ mL (round off to 2 decimal places)Correct answer is '1540.0 to 1542.0'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide. The amount of water that can be produced from 1 kg of tripalmitate is ____ mL (round off to 2 decimal places)Correct answer is '1540.0 to 1542.0'. Can you explain this answer?.
The complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide. The amount of water that can be produced from 1 kg of tripalmitate is ____ mL (round off to 2 decimal places)Correct answer is '1540.0 to 1542.0'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide. The amount of water that can be produced from 1 kg of tripalmitate is ____ mL (round off to 2 decimal places)Correct answer is '1540.0 to 1542.0'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide. The amount of water that can be produced from 1 kg of tripalmitate is ____ mL (round off to 2 decimal places)Correct answer is '1540.0 to 1542.0'. Can you explain this answer?.
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The complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide. The amount of water that can be produced from 1 kg of tripalmitate is ____ mL (round off to 2 decimal places)Correct answer is '1540.0 to 1542.0'. Can you explain this answer?, a detailed solution for The complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide. The amount of water that can be produced from 1 kg of tripalmitate is ____ mL (round off to 2 decimal places)Correct answer is '1540.0 to 1542.0'. Can you explain this answer? has been provided alongside types of The complete oxidation of one mole of palmitoyl CoA yields 23 moles of water and 16 moles of carbon dioxide. The amount of water that can be produced from 1 kg of tripalmitate is ____ mL (round off to 2 decimal places)Correct answer is '1540.0 to 1542.0'. Can you explain this answer? theory, EduRev gives you an
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