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A sphere of radius 12cm carries a charge 1.5×10^6 c which is uniformly distributed on the surface of sphere . calculate the electric field intensity just beyond the surface of sphere . Also at a distance of 18 cm from the centre of sphere
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A sphere of radius 12cm carries a charge 1.5×10^6 c which is uniformly...
Calculation of Electric Field Intensity
• To calculate the electric field intensity just beyond the surface of the sphere, we can treat the entire charge as concentrated at the center of the sphere.
• The formula for electric field intensity due to a point charge is E = k * Q / r^2, where k is the electrostatic constant, Q is the charge, and r is the distance from the charge.
• In this case, the charge Q = 1.5×10^6 C and r = radius of the sphere = 12 cm.
• The electrostatic constant k = 9 x 10^9 Nm^2/C^2.
• Substituting the values into the formula, we get E = (9 x 10^9) * (1.5 x 10^6) / (0.12)^2 = 1.125 x 10^16 / 0.0144 = 7.8125 x 10^17 N/C.
Electric Field Intensity at a Distance of 18 cm
• To calculate the electric field intensity at a distance of 18 cm from the center of the sphere, we need to consider the charge distribution on the surface of the sphere.
• We can use the formula for electric field intensity due to a charged sphere at a point outside the sphere, which is E = k * Q * r / R^3, where R is the radius of the sphere.
• In this case, Q = 1.5×10^6 C, r = 18 cm, and R = 12 cm.
• Substituting the values into the formula, we get E = (9 x 10^9) * (1.5 x 10^6) * (0.18) / (0.12)^3 = 2.43 x 10^16 / 0.1728 = 1.40625 x 10^17 N/C.
In conclusion, the electric field intensity just beyond the surface of the sphere is 7.8125 x 10^17 N/C, and at a distance of 18 cm from the center of the sphere, the electric field intensity is 1.40625 x 10^17 N/C.
• To calculate the electric field intensity just beyond the surface of the sphere, we can treat the entire charge as concentrated at the center of the sphere.
• The formula for electric field intensity due to a point charge is E = k * Q / r^2, where k is the electrostatic constant, Q is the charge, and r is the distance from the charge.
• In this case, the charge Q = 1.5×10^6 C and r = radius of the sphere = 12 cm.
• The electrostatic constant k = 9 x 10^9 Nm^2/C^2.
• Substituting the values into the formula, we get E = (9 x 10^9) * (1.5 x 10^6) / (0.12)^2 = 1.125 x 10^16 / 0.0144 = 7.8125 x 10^17 N/C.
Electric Field Intensity at a Distance of 18 cm
• To calculate the electric field intensity at a distance of 18 cm from the center of the sphere, we need to consider the charge distribution on the surface of the sphere.
• We can use the formula for electric field intensity due to a charged sphere at a point outside the sphere, which is E = k * Q * r / R^3, where R is the radius of the sphere.
• In this case, Q = 1.5×10^6 C, r = 18 cm, and R = 12 cm.
• Substituting the values into the formula, we get E = (9 x 10^9) * (1.5 x 10^6) * (0.18) / (0.12)^3 = 2.43 x 10^16 / 0.1728 = 1.40625 x 10^17 N/C.
In conclusion, the electric field intensity just beyond the surface of the sphere is 7.8125 x 10^17 N/C, and at a distance of 18 cm from the center of the sphere, the electric field intensity is 1.40625 x 10^17 N/C.
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A sphere of radius 12cm carries a charge 1.5×10^6 c which is uniformly...
1) 9.3×10^172) 4.1×10^17
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A sphere of radius 12cm carries a charge 1.5×10^6 c which is uniformly distributed on the surface of sphere . calculate the electric field intensity just beyond the surface of sphere . Also at a distance of 18 cm from the centre of sphere
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A sphere of radius 12cm carries a charge 1.5×10^6 c which is uniformly distributed on the surface of sphere . calculate the electric field intensity just beyond the surface of sphere . Also at a distance of 18 cm from the centre of sphere for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A sphere of radius 12cm carries a charge 1.5×10^6 c which is uniformly distributed on the surface of sphere . calculate the electric field intensity just beyond the surface of sphere . Also at a distance of 18 cm from the centre of sphere covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sphere of radius 12cm carries a charge 1.5×10^6 c which is uniformly distributed on the surface of sphere . calculate the electric field intensity just beyond the surface of sphere . Also at a distance of 18 cm from the centre of sphere.
A sphere of radius 12cm carries a charge 1.5×10^6 c which is uniformly distributed on the surface of sphere . calculate the electric field intensity just beyond the surface of sphere . Also at a distance of 18 cm from the centre of sphere for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A sphere of radius 12cm carries a charge 1.5×10^6 c which is uniformly distributed on the surface of sphere . calculate the electric field intensity just beyond the surface of sphere . Also at a distance of 18 cm from the centre of sphere covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sphere of radius 12cm carries a charge 1.5×10^6 c which is uniformly distributed on the surface of sphere . calculate the electric field intensity just beyond the surface of sphere . Also at a distance of 18 cm from the centre of sphere.
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