A bus starts from rest and attains a speed of 36 km/h in 10 min while ...
Problem Statement: A bus starts from rest and attains a speed of 36 km/h in 10 min while moving with uniform acceleration. Calculate the acceleration of the bus.
Solution:
Given,
Initial velocity (u) = 0 km/h
Final velocity (v) = 36 km/h
Time taken (t) = 10 min = 10/60 hours = 1/6 hours
We know that,
Acceleration (a) = (v - u)/t
Substituting the given values, we get
a = (36 - 0)/(1/6)
Simplifying, we get
a = 216 km/h^2
Therefore, the acceleration of the bus is 216 km/h^2.
Explanation:
To solve this problem, we need to use the formula for acceleration which is given as:
Acceleration (a) = (Final velocity (v) - Initial velocity (u))/Time taken (t)
Here, the initial velocity of the bus is 0 km/h as it starts from rest. The final velocity of the bus is 36 km/h as it attains this speed after 10 minutes of moving with uniform acceleration. We need to convert the time taken from minutes to hours as the units of velocity and acceleration are in km/h.
After substituting the given values in the formula, we get the acceleration of the bus as 216 km/h^2. This means that the bus is accelerating at a rate of 216 km/h^2.
A bus starts from rest and attains a speed of 36 km/h in 10 min while ...
We need to change 36 km/h into m/s then we have to multiply it with 5/18 m/s. = 3/50 m/s^ 2 = 0.06 m/s^2. Thus, acceleration is 0.06 m/s^2.
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