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Answer the questions are based on the following:
Two men are walking towards each other alongside a railway track. A freight train overtakes one of them in 20 seconds and exactly 10 minutes later meets the other man coming from the opposite direction. The train passes this man in 18 seconds. Assume the velocities are constant throughout.
Q. How long after the train has passed the second man will the two men meet?
  • a)
    89.7 minutes
  • b)
    90 minutes
  • c)
    90.3 minutes
  • d)
    cannot be determined
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Answer the questions are based on the following:Two men are walking t...
Solution:

Given that:

- A freight train overtakes one of the men in 20 seconds.
- The train meets the other man coming from the opposite direction exactly 10 minutes after overtaking the first man.
- The train passes the second man in 18 seconds.
- The velocities are constant throughout.

Let's assume that the speed of the train is 's' and the speeds of the two men are 'v1' and 'v2', respectively.

Finding the distance covered by the train while overtaking the first man:

- Distance = Speed × Time
- Distance covered by the train in 20 seconds = s × 20

Finding the distance between the two men when the train meets the second man:

- Distance covered by the train in 10 minutes (600 seconds) = s × 600
- Distance covered by the second man in 18 seconds = v2 × 18
- Total distance between the two men = Distance covered by the train + Distance covered by the second man
- Therefore, (s × 600) + (v2 × 18) = Distance covered by the train in 20 seconds

Finding the relative speed of the two men:

- Relative speed of the two men = v1 + v2

Finding the time taken for the two men to meet after the train passes the second man:

- Let's assume that the two men meet after 't' seconds.
- Distance covered by the train in 't' seconds = s × t
- Distance covered by the first man in 't' seconds = v1 × t
- Distance covered by the second man in 't' seconds = (v2 × t) + (18s)
- Total distance covered by the two men = Distance covered by the train
- Therefore, v1 × t + v2 × t + 18s = s × t
- Simplifying the above equation, we get t = 540 seconds = 9 minutes

Converting the time in minutes to minutes and seconds:

- 9 minutes = 9 × 60 seconds = 540 seconds

Therefore, the two men will meet 9 minutes after the train passes the second man. The correct answer is option 'B' (90 minutes).
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Community Answer
Answer the questions are based on the following:Two men are walking t...
Let L be length of the train, x,y,z speeds 1st man , 2nd man and train respectively.
L/(z-x) = 20, L/(y+z) = 18
Dividing the 2 equations, and solving, we have z = 9y + 10x.
Distance between persons when first train passes = 600(z+y)
Time = (600(z+y) - 600(x+y))/(x+y) = 600(10x+10y - (x+y))/(x+y) = 900 x 9 = 5400s
= 90 minutes
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Answer the questions are based on the following:Two men are walking towards each other alongside a railway track. A freight train overtakes one of them in 20 seconds and exactly 10 minutes later meets the other man coming from the opposite direction. The train passes this man in 18 seconds. Assume the velocities are constant throughout.Q. How long after the train has passed the second man will the two men meet?a)89.7 minutesb)90 minutesc)90.3 minutesd)cannot be determinede)None of theseCorrect answer is option 'B'. Can you explain this answer?
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