Swathi starts her job with a certain monthly salary and earns a fixed ...
Let Swathi's first salary is Rs. x & fixed increment is Rs. y
∴ Swathi's salary after 6 years = Rs. (x + 6y)
Swathi's salary after 11 years = Rs. (x + 11y)
Swathi's salary after 8 years = Rs. (x + 8y)
∴ x + 6y = 22500 ......(1)
& x + 11y = 30000 .......(2)
From (1) & (2), we get
22500 - 6y + 11y = 30000
⇒ 5y = 30000 - 22500
= 7500
⇒ y = 7500/5 = 1500
∴∴ From (1), we get
x = 22500 - 6y
= 22500 - 6 × 1500
= 22500 - 9000
= 13500
∴∴ Swathi's salary after 8 years of service = Rs. (x + 8y)
= Rs. (13500 + 8 × 1500)
= Rs. (13500 + 12000)
= Rs. 25500
Swathi starts her job with a certain monthly salary and earns a fixed ...
Given Information:
- Starting salary = Rs 22500 per month after 6 years
- Salary after 11 years = Rs 30000 per month
Calculating Increment per Year:
- Increment over 5 years = Rs 30000 - Rs 22500 = Rs 7500
- Increment per year = Rs 7500 / 5 = Rs 1500
Calculating Salary after 8 years:
- Increment after 2 years = Rs 1500 * 2 = Rs 3000
- Salary after 8 years = Rs 22500 + Rs 3000 = Rs 25500
Therefore, Swathi's salary after 8 years of service would be Rs 25500 per month, which corresponds to option B.