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A body moving with uniform acceleration has a velocity of –11 cm/s when its x coordinate is 3.00 cm. If its x coordinate 2 s later is – 5 cm, what is the magnitude in cm/s2 of its acceleration?
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A body moving with uniform acceleration has a velocity of –11 cm/s whe...
Given data:
- Initial velocity (u) = -11 cm/s
- Initial x coordinate (x1) = 3.00 cm
- Final x coordinate (x2) = -5 cm
- Time interval (t) = 2 s

Calculating acceleration:
- Using the equation of motion: \( x2 = x1 + ut + \frac{1}{2}at^2 \)
- Substituting the given values: -5 = 3 + (-11)(2) + 0.5a(2)^2
- Simplifying the equation: -5 = 3 - 22 + 2a
- Solving for acceleration (a): a = (-5 - 3 + 22) / 2 = 14 cm/s^2

Conclusion:
- The magnitude of the acceleration of the body is 14 cm/s^2.
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A body moving with uniform acceleration has a velocity of –11 cm/s when its x coordinate is 3.00 cm. If its x coordinate 2 s later is – 5 cm, what is the magnitude in cm/s2 of its acceleration?
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