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Consider the expression
Where a, b, c, d , ...... z are positive integers. The minimum value of the expression is
  • a)
    226√27! - 1
  • b)
    226√26!
  • c)
    227√26!
  • d)
    27!
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Consider the expression Where a, b, c, d , ...... z are positive int...
By AM-GM inequality
Multiplying, we get
Hence, option 2.
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Consider the expression Where a, b, c, d , ...... z are positive integers. The minimum value of the expression isa)226√27! - 1b)226√26!c)227√26!d)27!Correct answer is option 'B'. Can you explain this answer?
Question Description
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