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The sum of two times a positive number and three times another is 3 times the excess of five times the first over thrice the second. find the ratio of the first and the second number, (A) 12:13. (B)13:12 (C) 6:13 (D)13:6
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The sum of two times a positive number and three times another is 3 ti...
Problem: The sum of two times a positive number and three times another is 3 times the excess of five times the first over thrice the second. Find the ratio of the first and the second number.

Solution:
Let the two numbers be x and y, where x is the first number and y is the second number. Then according to the problem statement, we have:

2x + 3y = 3(5x/3 - y)

Simplifying this equation, we get:

2x + 3y = 5x - 3y

Adding 3y to both sides, we get:

2x + 6y = 5x

Subtracting 2x from both sides, we get:

4y = 3x

Dividing both sides by y, we get:

x/y = 3/4

Therefore, the ratio of the first and second number is 3:4 or 12:16, which simplifies to 12:13.

Answer: The ratio of the first and second number is 12:13, therefore the correct option is (A) 12:13.
Community Answer
The sum of two times a positive number and three times another is 3 ti...
A: 2x+3y=3(5x-3y)x/y=12/13
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The sum of two times a positive number and three times another is 3 times the excess of five times the first over thrice the second. find the ratio of the first and the second number, (A) 12:13. (B)13:12 (C) 6:13 (D)13:6
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