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Solve (x2 – y2) dx – xydy = 0
  • a)
    x2(x2 + 2y2) = constant
  • b)
    x2(x2 + 3y2) = constant
  • c)
    x2(x2 - 2y2) = constant
  • d)
    x2(2x2 - 2y2) = constant
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Solve (x2– y2) dx – xydy = 0a)x2(x2 + 2y2) = constantb)x2(...
(x2 – y2) dx – xydy = 0
This homogeneous in x & y
Separating the variables
Integrating on both side
⇒ 4logx + log⁡(1 − 2v2) = −4c
⇒ x2 (x2 – 2y2) = constant
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Community Answer
Solve (x2– y2) dx – xydy = 0a)x2(x2 + 2y2) = constantb)x2(...
(x2 – y2) dx – xydy = 0
This homogeneous in x & y
Separating the variables
Integrating on both side
⇒ 4logx + log⁡(1 − 2v2) = −4c
⇒ x2 (x2 – 2y2) = constant
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Solve (x2– y2) dx – xydy = 0a)x2(x2 + 2y2) = constantb)x2(x2 + 3y2) = constantc)x2(x2 - 2y2) = constantd)x2(2x2 - 2y2) = constantCorrect answer is option 'C'. Can you explain this answer?
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