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If the current through a moving iron instrument is increased by 20%, what is the percentage increase in the deflection torque?
  • a)
    40
  • b)
    25
  • c)
    32
  • d)
    44
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
If the current through a moving iron instrument is increased by 20%, w...
Increase in current through a moving iron instrument and the percentage increase in deflection torque are related through a mathematical equation. To find the percentage increase in deflection torque, we need to understand the relationship between the current and deflection torque.

The deflection torque in a moving iron instrument is given by the equation:

T = K * I^2

where T is the deflection torque, K is a constant, and I is the current passing through the instrument.

Let's say the initial current passing through the instrument is I1, and the final current after the increase is I2. The initial deflection torque is T1, and we need to find the percentage increase in deflection torque.

- Identify the given information:
- Initial current: I1
- Increase in current: 20%
- Final current: I2 = I1 + 0.2 * I1 = 1.2 * I1
- Initial deflection torque: T1
- Percentage increase in deflection torque: ?

- Calculate the final deflection torque:
- Substitute the values in the equation: T2 = K * (1.2 * I1)^2 = 1.44 * K * I1^2

- Calculate the percentage increase in deflection torque:
- Percentage increase = (T2 - T1) / T1 * 100%
- Substitute the values: (1.44 * K * I1^2 - K * I1^2) / K * I1^2 * 100%
- Simplify: 0.44 * 100% = 44%

Hence, the percentage increase in the deflection torque is 44%. Therefore, the correct answer is option D.
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Community Answer
If the current through a moving iron instrument is increased by 20%, w...
Concept:
In moving iron instruments, the deflecting torque is unidirectional (acts in the same direction) whatever may be the polarity of the current.
The deflecting torque is given by

Where,
I is operating current
L is self-inductance
θ is deflection
Td ∝ I2
So that the deflection torque of the moving iron instrument is proportional to the square of the RMS value of the operating current and change in self-inductance. 
Calculation:
When the current through a moving iron instrument is increased by 20%, then deflection torque is

∴ T'd = 1.44 Td
Hence deflection torque is increased by 44%
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