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The differential equationis valid in the domain 0 ≤ x ≤ 1 with y (0) = 2.25 The solution of the differential equation isa)y = e-4x+ 5b)y = e-4x+ 1.25c)y= e4x+ 5d)y= e4x+ 1.25Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The differential equationis valid in the domain 0 ≤ x ≤ 1 with y (0) = 2.25 The solution of the differential equation isa)y = e-4x+ 5b)y = e-4x+ 1.25c)y= e4x+ 5d)y= e4x+ 1.25Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The differential equationis valid in the domain 0 ≤ x ≤ 1 with y (0) = 2.25 The solution of the differential equation isa)y = e-4x+ 5b)y = e-4x+ 1.25c)y= e4x+ 5d)y= e4x+ 1.25Correct answer is option 'B'. Can you explain this answer?.

Solutions for The differential equationis valid in the domain 0 ≤ x ≤ 1 with y (0) = 2.25 The solution of the differential equation isa)y = e-4x+ 5b)y = e-4x+ 1.25c)y= e4x+ 5d)y= e4x+ 1.25Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.

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