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In the circuit shown in the given figure, the switch’s is open for a long time and closed at t = 0.
Correct answer is '-6'. Can you explain this answer?
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In the circuit shown in the given figure, the switch’s is open f...
At t < 0, the circuit will be at steady-state and the capacitor will be open-circuited as there is a DC current source.
For an open-circuited capacitor, the current from the 6 A source will be distributed equally between the two branches with 6 Ω and 2+4 = 6 Ω resistances.
∴ The current through the 4 Ω resistor will be 3 A.
The charge stored by the capacitor before the switch is just open will be:
Vc(0-) = 4 × 3 = 12 V
At t = 0+, all the current from the 6 A source will follow the short circuit path. The circuit will be redrawn as shown:
The capacitor can be replaced with a voltage source of 12 V. The current I will then be:
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In the circuit shown in the given figure, the switch’s is open for a long time and closed at t = 0.Correct answer is '-6'. Can you explain this answer?
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In the circuit shown in the given figure, the switch’s is open for a long time and closed at t = 0.Correct answer is '-6'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In the circuit shown in the given figure, the switch’s is open for a long time and closed at t = 0.Correct answer is '-6'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the circuit shown in the given figure, the switch’s is open for a long time and closed at t = 0.Correct answer is '-6'. Can you explain this answer?.
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