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In the single-pulse width modulation method, the Fourier coefficient bn is given by
- a)(Vs/π) [sin(nπ/2) sin(nd)].
- b)0
- c)(4Vs/nπ) [sin(nπ/2) sin(nd)].
- d)(2Vs/nπ) [sin(nπ/2) sin(nd)].
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In the single-pulse width modulation method, the Fourier coefficient b...
The Fourier analysis is as under:
bn = (2/π) ∫ Vs sin nωt .d(ωt) , Where the integration would run from (π/2 + d) to (π/2 – d)
2d is the width of the pulse.
bn = (2/π) ∫ Vs sin nωt .d(ωt) , Where the integration would run from (π/2 + d) to (π/2 – d)
2d is the width of the pulse.
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In the single-pulse width modulation method, the Fourier coefficient b...
In the single-pulse width modulation method, the Fourier coefficient bn is given by:
bn = (2Vs/T) * ∫[t_on, t_off] sin(nωt)dt
where bn is the nth Fourier coefficient, Vs is the amplitude of the sine wave that is being modulated, T is the period of the modulation signal, t_on is the starting time of the pulse, t_off is the ending time of the pulse, ω is the angular frequency (2πf) of the sine wave, and n is the order of the Fourier coefficient.
bn = (2Vs/T) * ∫[t_on, t_off] sin(nωt)dt
where bn is the nth Fourier coefficient, Vs is the amplitude of the sine wave that is being modulated, T is the period of the modulation signal, t_on is the starting time of the pulse, t_off is the ending time of the pulse, ω is the angular frequency (2πf) of the sine wave, and n is the order of the Fourier coefficient.
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In the single-pulse width modulation method, the Fourier coefficient bn is given bya)(Vs/π) [sin(nπ/2) sin(nd)].b)0c)(4Vs/nπ) [sin(nπ/2) sin(nd)].d)(2Vs/nπ) [sin(nπ/2) sin(nd)].Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In the single-pulse width modulation method, the Fourier coefficient bn is given bya)(Vs/π) [sin(nπ/2) sin(nd)].b)0c)(4Vs/nπ) [sin(nπ/2) sin(nd)].d)(2Vs/nπ) [sin(nπ/2) sin(nd)].Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the single-pulse width modulation method, the Fourier coefficient bn is given bya)(Vs/π) [sin(nπ/2) sin(nd)].b)0c)(4Vs/nπ) [sin(nπ/2) sin(nd)].d)(2Vs/nπ) [sin(nπ/2) sin(nd)].Correct answer is option 'C'. Can you explain this answer?.
In the single-pulse width modulation method, the Fourier coefficient bn is given bya)(Vs/π) [sin(nπ/2) sin(nd)].b)0c)(4Vs/nπ) [sin(nπ/2) sin(nd)].d)(2Vs/nπ) [sin(nπ/2) sin(nd)].Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In the single-pulse width modulation method, the Fourier coefficient bn is given bya)(Vs/π) [sin(nπ/2) sin(nd)].b)0c)(4Vs/nπ) [sin(nπ/2) sin(nd)].d)(2Vs/nπ) [sin(nπ/2) sin(nd)].Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the single-pulse width modulation method, the Fourier coefficient bn is given bya)(Vs/π) [sin(nπ/2) sin(nd)].b)0c)(4Vs/nπ) [sin(nπ/2) sin(nd)].d)(2Vs/nπ) [sin(nπ/2) sin(nd)].Correct answer is option 'C'. Can you explain this answer?.
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