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SCR with a rating of 1200 V and 250 A are available to be used in a string to handle 8 kV and 1kA. The number of parallel and series units required are respectively _____ (Take derating factor is 0.2)
  • a)
    8, 5
  • b)
    9, 5
  • c)
    5, 9
  • d)
    5, 8
Correct answer is option 'C'. Can you explain this answer?
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SCR with a rating of 1200 V and 250 A are available to be used in a st...
Derating factor = 1 – string efficiency
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SCR with a rating of 1200 V and 250 A are available to be used in a st...
Given parameters:
SCR rating: 1200 V, 250 A
Required parameters: 8 kV, 1 kA
Derating factor: 0.2

To determine the number of parallel and series units required, we need to consider both the voltage and current ratings of the SCR units.

1. Derating the voltage:
Since the derating factor is 0.2, the maximum allowable voltage for each SCR unit can be calculated as follows:
Maximum voltage = Rated voltage - (Rated voltage * Derating factor)
Maximum voltage = 1200 V - (1200 V * 0.2) = 960 V

To handle 8 kV, we need to determine the number of series units required:
Number of series units = Required voltage / Maximum voltage
Number of series units = 8000 V / 960 V = 8.33 ≈ 9 (rounded up to the nearest whole number)

2. Derating the current:
Since the derating factor is 0.2, the maximum allowable current for each SCR unit can be calculated as follows:
Maximum current = Rated current - (Rated current * Derating factor)
Maximum current = 250 A - (250 A * 0.2) = 200 A

To handle 1 kA, we need to determine the number of parallel units required:
Number of parallel units = Required current / Maximum current
Number of parallel units = 1000 A / 200 A = 5

Therefore, the number of parallel and series units required are respectively 5 and 9.

Hence, the correct answer is option C) 5, 9.
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SCR with a rating of 1200 V and 250 A are available to be used in a string to handle 8 kV and 1kA. The number of parallel and series units required are respectively _____ (Take derating factor is 0.2)a)8, 5b)9, 5c)5, 9d)5, 8Correct answer is option 'C'. Can you explain this answer?
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