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Carry out BCD subtraction for (68) – (61) using 10’s complement method.
  • a)
    00000111
  • b)
    01110000
  • c)
    100000111
  • d)
    011111000
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Carry out BCD subtraction for (68) – (61) using 10’s compl...
To carry out BCD subtraction for (68), we need to subtract the BCD (Binary-Coded Decimal) representation of 8 from the BCD representation of 6.

The BCD representation of 6 is 0110.
The BCD representation of 8 is 1000.

To perform the subtraction, we start with the least significant digit (rightmost) and work our way to the most significant digit (leftmost).

1. Subtract the BCD representation of 8 (1000) from the BCD representation of 6 (0110):
0110
- 1000

2. Starting from the rightmost digit, subtract the corresponding digits:
0 - 0 = 0
1 - 0 = 1
1 - 0 = 1
0 - 1 = 1 (borrow 1)

3. Move to the next digit and subtract the corresponding digits, including the borrow:
0 - 1 (borrowed) = 9 (carry 1)
1 - 0 = 1
1 - 0 = 1

4. The BCD representation of the result is 0111, which is equivalent to the decimal number 7.

Therefore, the BCD subtraction of (68) is (7).
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Community Answer
Carry out BCD subtraction for (68) – (61) using 10’s compl...
First the two numbers are converted into their respective BCD form using 8421 sequence. Then binary subtraction is carried out.
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