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If B,A,C are in ap and C,B,A are in gp then proved that A,C,B are in HP.?
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If B,A,C are in ap and C,B,A are in gp then proved that A,C,B are in H...
Given that A, B, C are in AP and C, B, A are in GP
A = (C + B) / 2
and C = AB/B
Substituting the value of C in A we get
A = (AB/B + B) / 2
A = (AB + B^2) / (2B)
Therefore, A, C, B are in HP.
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If B,A,C are in ap and C,B,A are in gp then proved that A,C,B are in H...



Proof that A, C, B are in HP


  1. Given information:
    • B, A, C are in AP: B, A, C are in arithmetic progression, so 2A = B + C.
    • C, B, A are in GP: C, B, A are in geometric progression, so B^2 = AC.




  2. Proof:
    • Since B, A, C are in AP, we have 2A = B + C.
    • Rearranging this equation, we get C = 2A - B.
    • Since C, B, A are in GP, we have B^2 = AC.
    • Substituting the value of C from the first equation into the second equation, we get B^2 = A(2A - B).
    • Simplifying this equation, we get B^2 = 2A^2 - AB.
    • Rearranging this equation, we get AB = 2A^2 - B^2.
    • Dividing by AB on both sides, we get 1 = 2A/B - B/A.
    • This equation represents the harmonic mean of A and B with respect to C.
    • Therefore, A, C, B are in HP (Harmonic Progression).





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If B,A,C are in ap and C,B,A are in gp then proved that A,C,B are in HP.?
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