The curve surface area of Right circular cylinder of height 40cm is 88...
The surface area of a right circular cylinder is given by the formula:
Surface area = 2πr^2 + 2πrh
Where r is the radius of the base of the cylinder, h is the height of the cylinder, and π (pi) is a mathematical constant approximately equal to 3.14.
If the surface area of a right circular cylinder is 88 cm^2 and the height is 40 cm, we can substitute these values into the formula to solve for the radius:
88 cm^2 = 2πr^2 + 2πrh
88 cm^2 = 2πr^2 + 2πr(40 cm)
88 cm^2 = 2πr^2 + 80πr
88 cm^2 - 80πr = 2πr^2
(88 cm^2 - 80πr)/2π = r^2
44 cm^2 - 40πr/2π = r^2
r^2 = 44 cm^2 - 40πr/2π
r^2 = 22 cm^2 - 20πr/π
r^2 = 22 cm^2 - 20r
r^2 + 20r - 22 cm^2 = 0
We can use the quadratic formula to solve for r:
r = (-20 +- √(400 + 880))/2
r = (-20 +- √1280)/2
r = (-20 +- 35.6)/2
The radius of the base of the cylinder is either 7.8 cm or -12.8 cm. However, the radius cannot be negative, so the radius must be 7.8 cm.
The diameter of the base of the cylinder is twice the radius, or 2 * 7.8 cm = 15.6 cm. Therefore, the diameter of the base of the cylinder is 15.6 cm.