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The pu parameters for a 300 MVA machine on its own base are inertia M = 10 pu and reactance X = 4 pu. The pu values of inertia and reactance on 50 MVA common base, respectively, will be:
  • a)
    60, 0.67
  • b)
    40, 0.67
  • c)
    60, 0.4
  • d)
    4, 10
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The pu parameters for a 300 MVA machine on its own base are inertia M ...
Given Data:
- Machine parameters on its own base: Inertia M = 10 pu, Reactance X = 4 pu
- Base MVA of the machine = 300 MVA
- New common base MVA = 50 MVA

Calculations:

Step 1: Calculating the new base values of inertia and reactance
- The new base MVA is 50 MVA, so the new base values of inertia and reactance can be calculated as follows:
- New Inertia = Old Inertia * (Old Base MVA / New Base MVA)
- New Inertia = 10 * (300 / 50) = 60 pu
- New Reactance = Old Reactance * (Old Base MVA / New Base MVA)
- New Reactance = 4 * (300 / 50) = 24 pu

Step 2: Converting the new base values to pu values
- To convert the new base values to pu values, divide them by the new base MVA:
- Inertia on 50 MVA base = 60 / 50 = 1.2 pu
- Reactance on 50 MVA base = 24 / 50 = 0.48 pu

Final Answer:
- The pu values of inertia and reactance on 50 MVA common base are 1.2 pu and 0.48 pu respectively.
Therefore, the correct answer is option A: 60, 0.67.
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Community Answer
The pu parameters for a 300 MVA machine on its own base are inertia M ...
Given that, pu parameters for a 300 MVA machine on its own base Inertia: Mold = 10 pu
Reactance: Xold = 4 pu
New base = 50 MVA
New pu value of inertia,

New pu value of reactance,


Note:
We know that Pu value depends on the base value of that quantity hence the actual value of that quantity is always equal-
pu value old = actual/old base
Now, new pu value = actual/new base
⇒ Puold × Base old = Punew × Basenew
⇒ pu new = (pu old × old base)/(new base) 
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Question Description
The pu parameters for a 300 MVA machine on its own base are inertia M = 10 pu and reactance X = 4 pu. The pu values of inertia and reactance on 50 MVA common base, respectively, will be:a)60, 0.67b)40, 0.67c)60, 0.4d)4, 10Correct answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The pu parameters for a 300 MVA machine on its own base are inertia M = 10 pu and reactance X = 4 pu. The pu values of inertia and reactance on 50 MVA common base, respectively, will be:a)60, 0.67b)40, 0.67c)60, 0.4d)4, 10Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The pu parameters for a 300 MVA machine on its own base are inertia M = 10 pu and reactance X = 4 pu. The pu values of inertia and reactance on 50 MVA common base, respectively, will be:a)60, 0.67b)40, 0.67c)60, 0.4d)4, 10Correct answer is option 'A'. Can you explain this answer?.
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