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The average of 7 natural numbers is 23.142857. If one number which is 7, is removed, it is observed that the other numbers are in the ratio 1:3:4:5:7:11, then find the difference between the largest and the second largest number.
  • a)
    12
  • b)
    16
  • c)
    20
  • d)
    24
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The average of 7 natural numbers is 23.142857. If one number which is...
Average of 7 numbers = 23.142857
Sum of the 7 numbers = 162
Sum of remaining 6 numbers + 7 = 162
Therefore, sum of other 6 remaining numbers = 155
Let the number be x, 3x, 4x, 5x, 7x, 11x.
Sum = 31x = 155
⇒ x = 5
Hence the largest number is 55, and the second largest number is 35, which has a difference of 20.
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The average of 7 natural numbers is 23.142857. If one number which is 7, is removed, it is observed that the other numbers are in the ratio 1:3:4:5:7:11, then find the difference between the largest and the second largest number.a)12b)16c)20d)24Correct answer is option 'C'. Can you explain this answer?
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