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A 50 Hz current has an amplitude of 25 A. The rate of change of current at t = 0.005 after i = 0 and is increasing is ____________
- a)2221.44 A/s
- b)0
- c)-2221.44 A/s
- d)-3141.6 A/s
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A 50 Hz current has an amplitude of 25 A. The rate of change of curren...
The current i (t) is given by,
i = 25 sin 314.16 t and di/dt = 250 X 314.16 cosωt
Now, at t = 0.005, I = 25 X 314.16 cos (314.16 X 0.005)
= 0.
i = 25 sin 314.16 t and di/dt = 250 X 314.16 cosωt
Now, at t = 0.005, I = 25 X 314.16 cos (314.16 X 0.005)
= 0.
Most Upvoted Answer
A 50 Hz current has an amplitude of 25 A. The rate of change of curren...
The current i (t) is given by,
i = 25 sin 314.16 t and di/dt = 250 X 314.16 cosωt
Now, at t = 0.005, I = 25 X 314.16 cos (314.16 X 0.005)
= 0.
i = 25 sin 314.16 t and di/dt = 250 X 314.16 cosωt
Now, at t = 0.005, I = 25 X 314.16 cos (314.16 X 0.005)
= 0.
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Community Answer
A 50 Hz current has an amplitude of 25 A. The rate of change of curren...
Given information:
- Frequency of the current = 50 Hz
- Amplitude of the current = 25 A
- Time at t = 0.005 s
- Initial current i = 0
- Current is increasing
Explanation:
Calculating angular frequency (ω):
ω = 2πf = 2 x 3.1416 x 50 = 314.16 rad/s
Finding the current at t = 0.005 s:
i(t) = I_max * sin(ωt)
i(0.005) = 25 * sin(314.16 x 0.005)
i(0.005) = 25 * sin(1.5708)
i(0.005) = 25 * 1 = 25 A
Calculating the rate of change of current:
Rate of change of current = di/dt = I_max * ω * cos(ωt)
At t = 0.005 s:
Rate of change of current = 25 * 314.16 * cos(1.5708)
Rate of change of current = 25 * 314.16 * 0
Rate of change of current = 0 A/s
Therefore, the rate of change of current at t = 0.005 s after i = 0 and is increasing is 0 A/s.
- Frequency of the current = 50 Hz
- Amplitude of the current = 25 A
- Time at t = 0.005 s
- Initial current i = 0
- Current is increasing
Explanation:
Calculating angular frequency (ω):
ω = 2πf = 2 x 3.1416 x 50 = 314.16 rad/s
Finding the current at t = 0.005 s:
i(t) = I_max * sin(ωt)
i(0.005) = 25 * sin(314.16 x 0.005)
i(0.005) = 25 * sin(1.5708)
i(0.005) = 25 * 1 = 25 A
Calculating the rate of change of current:
Rate of change of current = di/dt = I_max * ω * cos(ωt)
At t = 0.005 s:
Rate of change of current = 25 * 314.16 * cos(1.5708)
Rate of change of current = 25 * 314.16 * 0
Rate of change of current = 0 A/s
Therefore, the rate of change of current at t = 0.005 s after i = 0 and is increasing is 0 A/s.
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A 50 Hz current has an amplitude of 25 A. The rate of change of current at t = 0.005 after i = 0 and is increasing is ____________a)2221.44 A/sb)0c)-2221.44 A/sd)-3141.6 A/sCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 50 Hz current has an amplitude of 25 A. The rate of change of current at t = 0.005 after i = 0 and is increasing is ____________a)2221.44 A/sb)0c)-2221.44 A/sd)-3141.6 A/sCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 Hz current has an amplitude of 25 A. The rate of change of current at t = 0.005 after i = 0 and is increasing is ____________a)2221.44 A/sb)0c)-2221.44 A/sd)-3141.6 A/sCorrect answer is option 'B'. Can you explain this answer?.
A 50 Hz current has an amplitude of 25 A. The rate of change of current at t = 0.005 after i = 0 and is increasing is ____________a)2221.44 A/sb)0c)-2221.44 A/sd)-3141.6 A/sCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 50 Hz current has an amplitude of 25 A. The rate of change of current at t = 0.005 after i = 0 and is increasing is ____________a)2221.44 A/sb)0c)-2221.44 A/sd)-3141.6 A/sCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 Hz current has an amplitude of 25 A. The rate of change of current at t = 0.005 after i = 0 and is increasing is ____________a)2221.44 A/sb)0c)-2221.44 A/sd)-3141.6 A/sCorrect answer is option 'B'. Can you explain this answer?.
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