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Magnetic stored energy density for iron is given by ______
  • a)
    1/2 B/μ
  • b)
    1/2 B2 μ
  • c)
    1/2 ∅2 Rl
  • d)
    1/2 B2
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Magnetic stored energy density for iron is given by ______a)1/2 B/μ...
Explanation:

Magnetic Stored Energy Density Formula:
The magnetic stored energy density for iron is given by the formula: 1/2 B^2 / μ, where B is the magnetic flux density and μ is the permeability of the material.

Breaking Down the Formula:
- 1/2: This term represents half of the total energy stored in the magnetic field.
- B^2: This term represents the square of the magnetic flux density, indicating the strength of the magnetic field.
- μ: This term represents the permeability of the material, which determines how easily a material can be magnetized.

Significance of the Formula:
- The formula shows that the energy stored in a magnetic field is directly proportional to the square of the magnetic flux density.
- It also indicates that the energy stored is inversely proportional to the permeability of the material.

Application in Iron:
- In the case of iron, which is a ferromagnetic material with high permeability, the energy stored in its magnetic field is given by 1/2 B^2 / μ.
- This formula is important in understanding the behavior of magnetic materials and designing magnetic circuits in electrical engineering applications.

Conclusion:
The magnetic stored energy density for iron is expressed by the formula 1/2 B^2 / μ, which highlights the relationship between magnetic flux density, permeability, and energy stored in the magnetic field. This formula is essential for analyzing and designing magnetic systems in electrical engineering.
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Community Answer
Magnetic stored energy density for iron is given by ______a)1/2 B/μ...
Magnetic stored energy density for iron is given as
wfld = Wfld/((Length of the magnetic path through Iron)*(Iron area normal to the magnetic flux)) = 1/2 (F∅)/(length*Area) = 1/2 F/length ∅/area = 1/2 H*B
Also, H = B/μ,thus wfld = 1/2 B2/μ.
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