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In a balanced three-phase system-delta load, if we assume the line voltage is VRY = V∠0⁰ as a reference phasor. Then the source voltage VYB is?
- a)V∠0⁰
- b)V∠-120⁰
- c)V∠120⁰
- d)V∠240⁰
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In a balanced three-phase system-delta load, if we assume the line vol...
Phase voltage, then we can use the following formula to calculate the line current:
IL = IR + IY + IB
where IL is the line current, IR is the current flowing through the R phase, IY is the current flowing through the Y phase, and IB is the current flowing through the B phase.
We know that in a delta load, the line voltage is equal to the phase voltage, so we can substitute VRY for VR and get:
IL = IR + IY + IB = VR/R + VY/Y + VB/B
where R, Y, and B are the impedances of the load in the R, Y, and B phases, respectively.
Since the load is balanced, we can assume that R = Y = B = Z, where Z is the impedance of each phase. Therefore, we can simplify the equation to:
IL = (VR + VY + VB)/Z
Since the load is balanced, the phase currents are also equal, so we can use Ohm's Law to calculate the phase currents:
IR = VR/Z, IY = VY/Z, IB = VB/Z
Substituting these values into the equation for the line current, we get:
IL = (IR + IY + IB) = (VR/Z + VY/Z + VB/Z) = (VR + VY + VB)/Z
This confirms that the line current in a balanced three-phase system-delta load is equal to the sum of the phase currents divided by the impedance of each phase.
IL = IR + IY + IB
where IL is the line current, IR is the current flowing through the R phase, IY is the current flowing through the Y phase, and IB is the current flowing through the B phase.
We know that in a delta load, the line voltage is equal to the phase voltage, so we can substitute VRY for VR and get:
IL = IR + IY + IB = VR/R + VY/Y + VB/B
where R, Y, and B are the impedances of the load in the R, Y, and B phases, respectively.
Since the load is balanced, we can assume that R = Y = B = Z, where Z is the impedance of each phase. Therefore, we can simplify the equation to:
IL = (VR + VY + VB)/Z
Since the load is balanced, the phase currents are also equal, so we can use Ohm's Law to calculate the phase currents:
IR = VR/Z, IY = VY/Z, IB = VB/Z
Substituting these values into the equation for the line current, we get:
IL = (IR + IY + IB) = (VR/Z + VY/Z + VB/Z) = (VR + VY + VB)/Z
This confirms that the line current in a balanced three-phase system-delta load is equal to the sum of the phase currents divided by the impedance of each phase.
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In a balanced three-phase system-delta load, if we assume the line vol...
As the line voltage VRY = V∠0⁰ is taken as a reference phasor. Then the source voltage VYB is V∠-120⁰.
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In a balanced three-phase system-delta load, if we assume the line voltage is VRY = V∠0 as a reference phasor. Then the source voltage VYB is?a)V∠0b)V∠-120c)V∠120d)V∠240Correct answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In a balanced three-phase system-delta load, if we assume the line voltage is VRY = V∠0 as a reference phasor. Then the source voltage VYB is?a)V∠0b)V∠-120c)V∠120d)V∠240Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a balanced three-phase system-delta load, if we assume the line voltage is VRY = V∠0 as a reference phasor. Then the source voltage VYB is?a)V∠0b)V∠-120c)V∠120d)V∠240Correct answer is option 'B'. Can you explain this answer?.
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