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In abcd rhombus find value of x if da =12 bc=13 ab=x diagonals do =z ob=5 oc=y?
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In abcd rhombus find value of x if da =12 bc=13 ab=x diagonals do =z o...
Given Information:
- $AD = 12$
- $BC = 13$
- $AB = x$
- $DO = z$
- $OB = 5$
- $OC = y$

Finding the Value of x:
- In a rhombus, all sides are equal. Therefore, $AB = BC = x = 13$.

Finding the Value of z:
- In a rhombus, the diagonals bisect each other at right angles. Therefore, $DO = OC = z = y$.

Using Pythagorean Theorem to Find y:
- In triangle $DOB$, applying Pythagorean theorem: $OB^2 + OD^2 = BD^2$
- $5^2 + z^2 = 13^2$
- $25 + z^2 = 169$
- $z^2 = 144$
- $z = 12$

Conclusion:
- $x = 13$
- $z = 12$
- $y = 12$
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In abcd rhombus find value of x if da =12 bc=13 ab=x diagonals do =z ob=5 oc=y?
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