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Let p, q, r, s represents the following propositions.
p: x ∈ {8, 9, 10, 11, 12}
q: x is a composite number
r: x is a perfect square
s: x is a prime number
The integer x ≥ 2 which satisfies ¬ ((p ⇒ q) ∧ (¬ r ∨ ¬ s)) is __________ 
    Correct answer is '11'. Can you explain this answer?
    Most Upvoted Answer
    Let p, q, r, s represents the following propositions.p: x ∈ {8, 9...
    Understanding the Propositions
    To solve the expression ¬((p → q) ∧ (¬r ∨ ¬s), let's first clarify the propositions:
    - p: x ∈ {8, 9, 10, 11, 12}
    - q: x is a composite number
    - r: x is a perfect square
    - s: x is a prime number
    Evaluating Each Proposition for x = 11
    - For x = 11:
    - p: True (11 is in the set)
    - q: False (11 is prime, not composite)
    - r: False (11 is not a perfect square)
    - s: True (11 is prime)
    Breaking Down the Expression
    1. Evaluate p → q:
    - This translates to "If p is true, then q is true."
    - Since p is true and q is false, p → q is false.
    2. Evaluate ¬r:
    - Since r is false, ¬r is true.
    3. Evaluate ¬s:
    - Since s is true, ¬s is false.
    4. Evaluate ¬r ∨ ¬s:
    - This is true (true ∨ false = true).
    5. Combine Results:
    - Now substituting back: ¬((p → q) ∧ (¬r ∨ ¬s)) becomes ¬(false ∧ true).
    - This simplifies to ¬(false), which is true.
    Conclusion
    Since the expression is true for x = 11, it satisfies the condition. Hence, the integer x ≥ 2 that satisfies the original expression is:
    11
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    Community Answer
    Let p, q, r, s represents the following propositions.p: x ∈ {8, 9...
    Data:
    p: x ∈ {8, 9, 10, 11, 12}
    q: x is a composite number
    r: x is a perfect square
    s: x is a prime number
    Explanation:
    p ⇒ q means p̅ + q
    As, q is composite number So, p ⇒ results in {8, 9, 10, 12}
    As, r: x is a perfect square, ¬ r results in all the numbers which are not perfect square
    So, ¬ r: {8, 10, 11, 12}
    ¬ s: {8, 9, 10, 12}
    ¬ r ∨ ¬ s = {8, 9, 10, 11, 12}
    Now, (p ⇒ q) ∧ (¬ r ∨ ¬ s) = {8, 9, 10, 12}
    ¬ ((p ⇒ q) ∧ (¬ r ∨ ¬ s)) results in a number which is not present in ((p ⇒ q) ∧ (¬ r ∨ ¬ s))
    ¬ ((p ⇒ q) ∧ (¬ r ∨ ¬s)) will give {11}.
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    Let p, q, r, s represents the following propositions.p: x ∈ {8, 9, 10, 11, 12}q: x is a composite numberr: x is a perfect squares: x is a prime numberThe integer x ≥ 2 which satisfies ¬ ((p ⇒ q) ∧ (¬ r ∨ ¬ s)) is __________Correct answer is '11'. Can you explain this answer?
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