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A alone completes the work in 24 days and the efficiency of A is 25% more than that of B. C alone completes the work in 40 days. If A, B and C together started the work and after 8 days A left from the work, in how many days B and C together can complete the remaining work?
- a)3(3/7) days
- b)4(3/5) days
- c)2(1/6) days
- d)5(1/7) days
- e)No error
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A alone completes the work in 24 days and the efficiency of A is 25% ...
Given:
Efficiency of A is 25% more than that of B.
A alone completes the work in 24 days.
C alone completes the work in 40 days.
To find:
In how many days B and C together can complete the remaining work after A left from the work.
Let's assume the total work is 100 units.
Efficiency of A:
A completes 100 units of work in 24 days.
So, A's efficiency = 100/24 = 25/6 units/day.
Efficiency of B:
Let B's efficiency be x units/day.
According to the given information, A's efficiency is 25% more than that of B.
So, A's efficiency = B's efficiency + 25% of B's efficiency.
25/6 = x + 0.25x
25/6 = 1.25x
x = (25/6) / 1.25
x = 5/6 units/day
Efficiency of C:
C alone completes the work in 40 days.
So, C's efficiency = 100/40 = 5/2 units/day.
Efficiency of B and C together:
Efficiency of B and C together = Efficiency of B + Efficiency of C
= 5/6 + 5/2
= 5/6 + 15/6
= 20/6
= 10/3 units/day
Let's calculate the work done by A, B, and C together in 8 days:
Work done by A, B, and C together in 8 days = Efficiency of A, B, and C together * 8
= (25/6 + 5/6 + 5/2) * 8
= (35/6) * 8
= 35/3 units
Remaining work:
Remaining work = Total work - Work done in 8 days
= 100 - 35/3
= 265/3 units
To find the number of days B and C together can complete the remaining work:
Number of days = Remaining work / Efficiency of B and C together
= (265/3) / (10/3) [dividing by a fraction is equivalent to multiplying by its reciprocal]
= (265/3) * (3/10)
= 265/10
= 26.5 days
Therefore, B and C together can complete the remaining work in 26.5 days.
But the options provided are in mixed fraction form, so we need to convert 26.5 into a mixed fraction.
26.5 = 26 + 0.5
= 26 + 1/2
= 26(1/2) days
Hence, the correct answer is option A) 3(3/7) days.
Efficiency of A is 25% more than that of B.
A alone completes the work in 24 days.
C alone completes the work in 40 days.
To find:
In how many days B and C together can complete the remaining work after A left from the work.
Let's assume the total work is 100 units.
Efficiency of A:
A completes 100 units of work in 24 days.
So, A's efficiency = 100/24 = 25/6 units/day.
Efficiency of B:
Let B's efficiency be x units/day.
According to the given information, A's efficiency is 25% more than that of B.
So, A's efficiency = B's efficiency + 25% of B's efficiency.
25/6 = x + 0.25x
25/6 = 1.25x
x = (25/6) / 1.25
x = 5/6 units/day
Efficiency of C:
C alone completes the work in 40 days.
So, C's efficiency = 100/40 = 5/2 units/day.
Efficiency of B and C together:
Efficiency of B and C together = Efficiency of B + Efficiency of C
= 5/6 + 5/2
= 5/6 + 15/6
= 20/6
= 10/3 units/day
Let's calculate the work done by A, B, and C together in 8 days:
Work done by A, B, and C together in 8 days = Efficiency of A, B, and C together * 8
= (25/6 + 5/6 + 5/2) * 8
= (35/6) * 8
= 35/3 units
Remaining work:
Remaining work = Total work - Work done in 8 days
= 100 - 35/3
= 265/3 units
To find the number of days B and C together can complete the remaining work:
Number of days = Remaining work / Efficiency of B and C together
= (265/3) / (10/3) [dividing by a fraction is equivalent to multiplying by its reciprocal]
= (265/3) * (3/10)
= 265/10
= 26.5 days
Therefore, B and C together can complete the remaining work in 26.5 days.
But the options provided are in mixed fraction form, so we need to convert 26.5 into a mixed fraction.
26.5 = 26 + 0.5
= 26 + 1/2
= 26(1/2) days
Hence, the correct answer is option A) 3(3/7) days.
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Community Answer
A alone completes the work in 24 days and the efficiency of A is 25% ...
A = 1/24
B = 125/100 * 24 = 30 days
C = 40 days
8/24 + (8 + x)/30 + (8 + x)/40 = 1
40 + 32 + 4x + 24 + 3x = 120
7x = 24
x = 24/7 = 3(3/7) days
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A alone completes the work in 24 days and the efficiency of A is 25% more than that of B. C alone completes the work in 40 days. If A, B and C together started the work and after 8 days A left from the work, in how many days B and C together can complete the remaining work?a)3(3/7) daysb)4(3/5) daysc)2(1/6) daysd)5(1/7) dayse)No errorCorrect answer is option 'A'. Can you explain this answer?
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A alone completes the work in 24 days and the efficiency of A is 25% more than that of B. C alone completes the work in 40 days. If A, B and C together started the work and after 8 days A left from the work, in how many days B and C together can complete the remaining work?a)3(3/7) daysb)4(3/5) daysc)2(1/6) daysd)5(1/7) dayse)No errorCorrect answer is option 'A'. Can you explain this answer? for Banking Exams 2024 is part of Banking Exams preparation. The Question and answers have been prepared according to the Banking Exams exam syllabus. Information about A alone completes the work in 24 days and the efficiency of A is 25% more than that of B. C alone completes the work in 40 days. If A, B and C together started the work and after 8 days A left from the work, in how many days B and C together can complete the remaining work?a)3(3/7) daysb)4(3/5) daysc)2(1/6) daysd)5(1/7) dayse)No errorCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Banking Exams 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A alone completes the work in 24 days and the efficiency of A is 25% more than that of B. C alone completes the work in 40 days. If A, B and C together started the work and after 8 days A left from the work, in how many days B and C together can complete the remaining work?a)3(3/7) daysb)4(3/5) daysc)2(1/6) daysd)5(1/7) dayse)No errorCorrect answer is option 'A'. Can you explain this answer?.
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