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Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,
I) x2 - 29x + 190 = 0
II) y2 + 7y – 170 = 0
- a)x > y
- b)x ≥ y
- c)x = y or relationship can’t be determined.
- d)x < />
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Following question contains two equations as I and II. You have to so...
To solve the given equations, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Solving Equation I:
I) x^2 - 29x + 190 = 0
Comparing this equation with the general form ax^2 + bx + c = 0, we can see that a = 1, b = -29, and c = 190.
Now, using the quadratic formula:
x = (-(-29) ± √((-29)^2 - 4(1)(190))) / (2(1))
x = (29 ± √(841 - 760)) / 2
x = (29 ± √81) / 2
x = (29 ± 9) / 2
So, the solutions for Equation I are:
x1 = (29 + 9) / 2 = 38 / 2 = 19
x2 = (29 - 9) / 2 = 20 / 2 = 10
Solving Equation II:
II) y^2 + 7y - 170 = 0
Comparing this equation with the general form ax^2 + bx + c = 0, we can see that a = 1, b = 7, and c = -170.
Using the quadratic formula:
y = (-7 ± √(7^2 - 4(1)(-170))) / (2(1))
y = (-7 ± √(49 + 680)) / 2
y = (-7 ± √729) / 2
y = (-7 ± 27) / 2
So, the solutions for Equation II are:
y1 = (-7 + 27) / 2 = 20 / 2 = 10
y2 = (-7 - 27) / 2 = -34 / 2 = -17
Determining the Relationship:
Comparing the solutions of x and y, we can see that:
x1 = 19
x2 = 10
y1 = 10
y2 = -17
From the solutions, we can conclude that x > y. Therefore, the relationship between the two equations is x > y.
Hence, the correct answer is option B) x ≥ y.
x = (-b ± √(b^2 - 4ac)) / (2a)
Solving Equation I:
I) x^2 - 29x + 190 = 0
Comparing this equation with the general form ax^2 + bx + c = 0, we can see that a = 1, b = -29, and c = 190.
Now, using the quadratic formula:
x = (-(-29) ± √((-29)^2 - 4(1)(190))) / (2(1))
x = (29 ± √(841 - 760)) / 2
x = (29 ± √81) / 2
x = (29 ± 9) / 2
So, the solutions for Equation I are:
x1 = (29 + 9) / 2 = 38 / 2 = 19
x2 = (29 - 9) / 2 = 20 / 2 = 10
Solving Equation II:
II) y^2 + 7y - 170 = 0
Comparing this equation with the general form ax^2 + bx + c = 0, we can see that a = 1, b = 7, and c = -170.
Using the quadratic formula:
y = (-7 ± √(7^2 - 4(1)(-170))) / (2(1))
y = (-7 ± √(49 + 680)) / 2
y = (-7 ± √729) / 2
y = (-7 ± 27) / 2
So, the solutions for Equation II are:
y1 = (-7 + 27) / 2 = 20 / 2 = 10
y2 = (-7 - 27) / 2 = -34 / 2 = -17
Determining the Relationship:
Comparing the solutions of x and y, we can see that:
x1 = 19
x2 = 10
y1 = 10
y2 = -17
From the solutions, we can conclude that x > y. Therefore, the relationship between the two equations is x > y.
Hence, the correct answer is option B) x ≥ y.
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Community Answer
Following question contains two equations as I and II. You have to so...
X2- 29x + 190 = 0
x2– 19x - 10x + 190 = 0
x(x - 19) – 10(x - 19) = 0
(x - 19)(x - 10) = 0
x = 19, 10
y2 + 7y – 170 = 0
y2 + 17y - 10y – 170 = 0
y(y + 17) - 10(y + 17) = 0
(y - 10)(y + 17) = 0
y = 10, -17
x ≥ y
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Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,I) x2 - 29x + 190 = 0II) y2 + 7y – 170 = 0a)x > yb)x ≥ yc)x = y or relationship can’t be determined.d)x e)None of theseCorrect answer is option 'B'. Can you explain this answer?
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Solutions for Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,I) x2 - 29x + 190 = 0II) y2 + 7y – 170 = 0a)x > yb)x ≥ yc)x = y or relationship can’t be determined.d)x e)None of theseCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Banking Exams.
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