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ABCD is a quadrilateral with diagonal AC and BD intersecting at O . if ar(ΔDOC) = ar ( ΔAOB), show that /BDA = / DBC?
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ABCD is a quadrilateral with diagonal AC and BD intersecting at O . if...
Ar (AOB) =Ar (DOC)

Adding ar(BOC) to both side

Ar (ACB)=Ar (DBC)

We know triangles having same base and equal areas lies between same paralles

Therefore, AD|| BC

Now angle BDA = DBC ( alternate interior angle )

Hence proved

That's all 🙂
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ABCD is a quadrilateral with diagonal AC and BD intersecting at O . if ar(ΔDOC) = ar ( ΔAOB), show that /BDA = / DBC?
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