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An orthogonal turning operation is carried out under the following conditions: rake angle = 5°, spindle rotational speed = 400 rpm, axial feed = 0.4 m/min and chip flow velocity =10 m/min. The chip thickness is found to be 3 mm. If mean thickness of primary shear zone is 0.025 mm, the shear strain rate (per sec) during the process is x 103. (Rounded to two decimal places only).Correct answer is '20.5'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about An orthogonal turning operation is carried out under the following conditions: rake angle = 5°, spindle rotational speed = 400 rpm, axial feed = 0.4 m/min and chip flow velocity =10 m/min. The chip thickness is found to be 3 mm. If mean thickness of primary shear zone is 0.025 mm, the shear strain rate (per sec) during the process is x 103. (Rounded to two decimal places only).Correct answer is '20.5'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An orthogonal turning operation is carried out under the following conditions: rake angle = 5°, spindle rotational speed = 400 rpm, axial feed = 0.4 m/min and chip flow velocity =10 m/min. The chip thickness is found to be 3 mm. If mean thickness of primary shear zone is 0.025 mm, the shear strain rate (per sec) during the process is x 103. (Rounded to two decimal places only).Correct answer is '20.5'. Can you explain this answer?.

Solutions for An orthogonal turning operation is carried out under the following conditions: rake angle = 5°, spindle rotational speed = 400 rpm, axial feed = 0.4 m/min and chip flow velocity =10 m/min. The chip thickness is found to be 3 mm. If mean thickness of primary shear zone is 0.025 mm, the shear strain rate (per sec) during the process is x 103. (Rounded to two decimal places only).Correct answer is '20.5'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.

Here you can find the meaning of An orthogonal turning operation is carried out under the following conditions: rake angle = 5°, spindle rotational speed = 400 rpm, axial feed = 0.4 m/min and chip flow velocity =10 m/min. The chip thickness is found to be 3 mm. If mean thickness of primary shear zone is 0.025 mm, the shear strain rate (per sec) during the process is x 103. (Rounded to two decimal places only).Correct answer is '20.5'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of An orthogonal turning operation is carried out under the following conditions: rake angle = 5°, spindle rotational speed = 400 rpm, axial feed = 0.4 m/min and chip flow velocity =10 m/min. The chip thickness is found to be 3 mm. If mean thickness of primary shear zone is 0.025 mm, the shear strain rate (per sec) during the process is x 103. (Rounded to two decimal places only).Correct answer is '20.5'. Can you explain this answer?, a detailed solution for An orthogonal turning operation is carried out under the following conditions: rake angle = 5°, spindle rotational speed = 400 rpm, axial feed = 0.4 m/min and chip flow velocity =10 m/min. The chip thickness is found to be 3 mm. If mean thickness of primary shear zone is 0.025 mm, the shear strain rate (per sec) during the process is x 103. (Rounded to two decimal places only).Correct answer is '20.5'. Can you explain this answer? has been provided alongside types of An orthogonal turning operation is carried out under the following conditions: rake angle = 5°, spindle rotational speed = 400 rpm, axial feed = 0.4 m/min and chip flow velocity =10 m/min. The chip thickness is found to be 3 mm. If mean thickness of primary shear zone is 0.025 mm, the shear strain rate (per sec) during the process is x 103. (Rounded to two decimal places only).Correct answer is '20.5'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice An orthogonal turning operation is carried out under the following conditions: rake angle = 5°, spindle rotational speed = 400 rpm, axial feed = 0.4 m/min and chip flow velocity =10 m/min. The chip thickness is found to be 3 mm. If mean thickness of primary shear zone is 0.025 mm, the shear strain rate (per sec) during the process is x 103. (Rounded to two decimal places only).Correct answer is '20.5'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.