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What will be the percentage change in cutting speed required to give an 80% reduction in tool life (i.e. to reduce tool life to one-fifth of its former value), when the value of n = 0.12. (Answer up to one decimal places)
Correct answer is '21.3'. Can you explain this answer?
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What will be the percentage change in cutting speed required to give ...
Calculation of Percentage Change in Cutting Speed
Given data:
n = 0.12
Reduction in tool life (T) = 80%
New tool life (T1) = T/5 = 20%
We know that the Taylor's tool life equation is given by:
T1/T = (V1/V)^n
Where,
T = Tool life
V = Cutting speed
n = Exponent for the material being machined
So, we can write the above equation as:
(V1/V)^n = T1/T
(V1/V)^0.12 = 0.2/1 (Substituting the given values)
(V1/V) = (0.2/1)^1/0.12
(V1/V) = 0.686
Now, we need to find the percentage change in cutting speed required to reduce tool life by 80%. This can be calculated using the following formula:
Percentage change in V = [(V1 - V)/V] x 100
Substituting the values, we get:
[(0.686V - V)/V] x 100 = -21.3%
Therefore, the percentage change in cutting speed required to give an 80% reduction in tool life when n = 0.12 is -21.3%.
Given data:
n = 0.12
Reduction in tool life (T) = 80%
New tool life (T1) = T/5 = 20%
We know that the Taylor's tool life equation is given by:
T1/T = (V1/V)^n
Where,
T = Tool life
V = Cutting speed
n = Exponent for the material being machined
So, we can write the above equation as:
(V1/V)^n = T1/T
(V1/V)^0.12 = 0.2/1 (Substituting the given values)
(V1/V) = (0.2/1)^1/0.12
(V1/V) = 0.686
Now, we need to find the percentage change in cutting speed required to reduce tool life by 80%. This can be calculated using the following formula:
Percentage change in V = [(V1 - V)/V] x 100
Substituting the values, we get:
[(0.686V - V)/V] x 100 = -21.3%
Therefore, the percentage change in cutting speed required to give an 80% reduction in tool life when n = 0.12 is -21.3%.
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What will be the percentage change in cutting speed required to give ...
Increasing in cutting speed = 21.3%Attention Mechanical Engineering Students!
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What will be the percentage change in cutting speed required to give an 80% reduction in tool life (i.e. to reduce tool life to one-fifth of its former value), when the value of n = 0.12. (Answer up to one decimal places)Correct answer is '21.3'. Can you explain this answer?
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What will be the percentage change in cutting speed required to give an 80% reduction in tool life (i.e. to reduce tool life to one-fifth of its former value), when the value of n = 0.12. (Answer up to one decimal places)Correct answer is '21.3'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about What will be the percentage change in cutting speed required to give an 80% reduction in tool life (i.e. to reduce tool life to one-fifth of its former value), when the value of n = 0.12. (Answer up to one decimal places)Correct answer is '21.3'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the percentage change in cutting speed required to give an 80% reduction in tool life (i.e. to reduce tool life to one-fifth of its former value), when the value of n = 0.12. (Answer up to one decimal places)Correct answer is '21.3'. Can you explain this answer?.
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