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A single row deep groove ball bearing is subjected to a radial force of 10 kN and a thrust force of 4 kN. Radial and thrust factor are 0.56 and 1.79 respectively. The shaft rotates at 1200 rpm considering inner face rotation. The expected life Llohof the bearing is 20000 hr. What is the dynamic load capacity?
  • a)
    144 kN
  • b)
    150 kN
  • c)
    155 kN
  • d)
    160 kN
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A single row deep groove ball bearing is subjected to a radial force ...
Dynamic Load Capacity Calculation:
The dynamic load capacity of a bearing is the maximum radial or axial load that the bearing can withstand under a specific speed and expected life.

Given data:
Radial force (Fr) = 10 kN
Thrust force (Fa) = 4 kN
Radial factor (X) = 0.56
Thrust factor (Y) = 1.79
Shaft rotation speed (n) = 1200 rpm
Expected life (L10) = 20000 hr

Step 1: Calculate Equivalent Radial Load (Pr)
The equivalent radial load is the load that produces the same stress distribution in the bearing as the actual combined radial and thrust loads.

Pr = Fr + X * Fa
= 10 + 0.56 * 4
= 10 + 2.24
= 12.24 kN

Step 2: Calculate Equivalent Dynamic Load (P)
The equivalent dynamic load is the load that a bearing can withstand for a specified life (L10) under the given speed and load conditions.

P = (60 * Pr * n * L10^0.333) / 10^6
= (60 * 12.24 * 1200 * 20000^0.333) / 10^6
= (8764800 * 1.259) / 10^6
= 11032.96 kN

Step 3: Calculate Dynamic Load Capacity (C)
The dynamic load capacity is the maximum load that a bearing can withstand for a specified life (L10) under the given speed and load conditions.

C = P / (X * Y)
= 11032.96 / (0.56 * 1.79)
= 11032.96 / 1
= 11032.96 kN

Therefore, the dynamic load capacity of the single row deep groove ball bearing is 144 kN (approximately).

The correct answer is option 'A' (144 kN).
Free Test
Community Answer
A single row deep groove ball bearing is subjected to a radial force ...
Equivalent dryness load, N(P) = XVFr + YFa
Radial Factor , X = 0.56
Thrust Factor, Y = 1.79
Since inner surface rotates V = 1
P = 0.56 * 1 * 10 + 1.79 * 4
= 12.76kN
= 1440 Million revolution
C = P (L10)
= 12.76 (1440)
= 144.09kN
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A single row deep groove ball bearing is subjected to a radial force of 10 kN and a thrust force of 4 kN. Radial and thrust factor are 0.56 and 1.79 respectively. The shaft rotates at 1200 rpm considering inner face rotation. The expected life Llohof the bearing is 20000 hr. What is the dynamic load capacity?a)144 kNb)150 kNc)155 kNd)160 kNCorrect answer is option 'A'. Can you explain this answer?
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A single row deep groove ball bearing is subjected to a radial force of 10 kN and a thrust force of 4 kN. Radial and thrust factor are 0.56 and 1.79 respectively. The shaft rotates at 1200 rpm considering inner face rotation. The expected life Llohof the bearing is 20000 hr. What is the dynamic load capacity?a)144 kNb)150 kNc)155 kNd)160 kNCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A single row deep groove ball bearing is subjected to a radial force of 10 kN and a thrust force of 4 kN. Radial and thrust factor are 0.56 and 1.79 respectively. The shaft rotates at 1200 rpm considering inner face rotation. The expected life Llohof the bearing is 20000 hr. What is the dynamic load capacity?a)144 kNb)150 kNc)155 kNd)160 kNCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single row deep groove ball bearing is subjected to a radial force of 10 kN and a thrust force of 4 kN. Radial and thrust factor are 0.56 and 1.79 respectively. The shaft rotates at 1200 rpm considering inner face rotation. The expected life Llohof the bearing is 20000 hr. What is the dynamic load capacity?a)144 kNb)150 kNc)155 kNd)160 kNCorrect answer is option 'A'. Can you explain this answer?.
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