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Two bodies A and B have thermal emissivities of 0.01 and 0.81, respectively. The outer surface areas of the two bodies are the same. The two bodies emit total radiant power at the same rate. The wavelength λB corresponding to maximum spectral radiancy in the radiation from B shifted from the wavelength corresponding to maximum spectral radiancy in the radiation from A, by 1.00 μ m. If the temperature of A is 5802 K, thena)the temperature of B is 1934 Kb)λB = 1.5 μ mc)the temperature of B is 11604 Kd)the temperature of B is 2901 KCorrect answer is option 'A,B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two bodies A and B have thermal emissivities of 0.01 and 0.81, respectively. The outer surface areas of the two bodies are the same. The two bodies emit total radiant power at the same rate. The wavelength λB corresponding to maximum spectral radiancy in the radiation from B shifted from the wavelength corresponding to maximum spectral radiancy in the radiation from A, by 1.00 μ m. If the temperature of A is 5802 K, thena)the temperature of B is 1934 Kb)λB = 1.5 μ mc)the temperature of B is 11604 Kd)the temperature of B is 2901 KCorrect answer is option 'A,B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two bodies A and B have thermal emissivities of 0.01 and 0.81, respectively. The outer surface areas of the two bodies are the same. The two bodies emit total radiant power at the same rate. The wavelength λB corresponding to maximum spectral radiancy in the radiation from B shifted from the wavelength corresponding to maximum spectral radiancy in the radiation from A, by 1.00 μ m. If the temperature of A is 5802 K, thena)the temperature of B is 1934 Kb)λB = 1.5 μ mc)the temperature of B is 11604 Kd)the temperature of B is 2901 KCorrect answer is option 'A,B'. Can you explain this answer?.

Solutions for Two bodies A and B have thermal emissivities of 0.01 and 0.81, respectively. The outer surface areas of the two bodies are the same. The two bodies emit total radiant power at the same rate. The wavelength λB corresponding to maximum spectral radiancy in the radiation from B shifted from the wavelength corresponding to maximum spectral radiancy in the radiation from A, by 1.00 μ m. If the temperature of A is 5802 K, thena)the temperature of B is 1934 Kb)λB = 1.5 μ mc)the temperature of B is 11604 Kd)the temperature of B is 2901 KCorrect answer is option 'A,B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Two bodies A and B have thermal emissivities of 0.01 and 0.81, respectively. The outer surface areas of the two bodies are the same. The two bodies emit total radiant power at the same rate. The wavelength λB corresponding to maximum spectral radiancy in the radiation from B shifted from the wavelength corresponding to maximum spectral radiancy in the radiation from A, by 1.00 μ m. If the temperature of A is 5802 K, thena)the temperature of B is 1934 Kb)λB = 1.5 μ mc)the temperature of B is 11604 Kd)the temperature of B is 2901 KCorrect answer is option 'A,B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Two bodies A and B have thermal emissivities of 0.01 and 0.81, respectively. The outer surface areas of the two bodies are the same. The two bodies emit total radiant power at the same rate. The wavelength λB corresponding to maximum spectral radiancy in the radiation from B shifted from the wavelength corresponding to maximum spectral radiancy in the radiation from A, by 1.00 μ m. If the temperature of A is 5802 K, thena)the temperature of B is 1934 Kb)λB = 1.5 μ mc)the temperature of B is 11604 Kd)the temperature of B is 2901 KCorrect answer is option 'A,B'. Can you explain this answer?, a detailed solution for Two bodies A and B have thermal emissivities of 0.01 and 0.81, respectively. The outer surface areas of the two bodies are the same. The two bodies emit total radiant power at the same rate. The wavelength λB corresponding to maximum spectral radiancy in the radiation from B shifted from the wavelength corresponding to maximum spectral radiancy in the radiation from A, by 1.00 μ m. If the temperature of A is 5802 K, thena)the temperature of B is 1934 Kb)λB = 1.5 μ mc)the temperature of B is 11604 Kd)the temperature of B is 2901 KCorrect answer is option 'A,B'. Can you explain this answer? has been provided alongside types of Two bodies A and B have thermal emissivities of 0.01 and 0.81, respectively. The outer surface areas of the two bodies are the same. The two bodies emit total radiant power at the same rate. The wavelength λB corresponding to maximum spectral radiancy in the radiation from B shifted from the wavelength corresponding to maximum spectral radiancy in the radiation from A, by 1.00 μ m. If the temperature of A is 5802 K, thena)the temperature of B is 1934 Kb)λB = 1.5 μ mc)the temperature of B is 11604 Kd)the temperature of B is 2901 KCorrect answer is option 'A,B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Two bodies A and B have thermal emissivities of 0.01 and 0.81, respectively. The outer surface areas of the two bodies are the same. The two bodies emit total radiant power at the same rate. The wavelength λB corresponding to maximum spectral radiancy in the radiation from B shifted from the wavelength corresponding to maximum spectral radiancy in the radiation from A, by 1.00 μ m. If the temperature of A is 5802 K, thena)the temperature of B is 1934 Kb)λB = 1.5 μ mc)the temperature of B is 11604 Kd)the temperature of B is 2901 KCorrect answer is option 'A,B'. Can you explain this answer? tests, examples and also practice JEE tests.