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A sphere of mass MM and radius R rests on two supports of the same height. One support is stationary while the other is moving with a velocity v = √2 m s−1 (see in the diagram). Assume the stationary support is rough and the moving support is frictionless so that the sphere is slipping at B. At the instant shown, AB = R√2=R2. Find the speed (in m s−1) of the centre of the sphere at the given instant.
    Correct answer is '1'. Can you explain this answer?
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    A sphere of mass MM and radius R rests on two supports of the same he...
    The sphere is rotating about point A, so the net velocity of point O will be along OB(assume u).
    Applying wedge constraint at point of contact B between sphere and block,
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    A sphere of mass MM and radius R rests on two supports of the same height. One support is stationary while the other is moving with a velocity v = √2 m s−1 (see in the diagram). Assume the stationary support is rough and the moving support is frictionless so that the sphere is slipping at B. At the instant shown, AB = R√2=R2. Find the speed (in m s−1) of the centre of the sphere at the given instant.Correct answer is '1'. Can you explain this answer?
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    A sphere of mass MM and radius R rests on two supports of the same height. One support is stationary while the other is moving with a velocity v = √2 m s−1 (see in the diagram). Assume the stationary support is rough and the moving support is frictionless so that the sphere is slipping at B. At the instant shown, AB = R√2=R2. Find the speed (in m s−1) of the centre of the sphere at the given instant.Correct answer is '1'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A sphere of mass MM and radius R rests on two supports of the same height. One support is stationary while the other is moving with a velocity v = √2 m s−1 (see in the diagram). Assume the stationary support is rough and the moving support is frictionless so that the sphere is slipping at B. At the instant shown, AB = R√2=R2. Find the speed (in m s−1) of the centre of the sphere at the given instant.Correct answer is '1'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sphere of mass MM and radius R rests on two supports of the same height. One support is stationary while the other is moving with a velocity v = √2 m s−1 (see in the diagram). Assume the stationary support is rough and the moving support is frictionless so that the sphere is slipping at B. At the instant shown, AB = R√2=R2. Find the speed (in m s−1) of the centre of the sphere at the given instant.Correct answer is '1'. Can you explain this answer?.
    Solutions for A sphere of mass MM and radius R rests on two supports of the same height. One support is stationary while the other is moving with a velocity v = √2 m s−1 (see in the diagram). Assume the stationary support is rough and the moving support is frictionless so that the sphere is slipping at B. At the instant shown, AB = R√2=R2. Find the speed (in m s−1) of the centre of the sphere at the given instant.Correct answer is '1'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
    Here you can find the meaning of A sphere of mass MM and radius R rests on two supports of the same height. One support is stationary while the other is moving with a velocity v = √2 m s−1 (see in the diagram). Assume the stationary support is rough and the moving support is frictionless so that the sphere is slipping at B. At the instant shown, AB = R√2=R2. Find the speed (in m s−1) of the centre of the sphere at the given instant.Correct answer is '1'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A sphere of mass MM and radius R rests on two supports of the same height. One support is stationary while the other is moving with a velocity v = √2 m s−1 (see in the diagram). Assume the stationary support is rough and the moving support is frictionless so that the sphere is slipping at B. At the instant shown, AB = R√2=R2. Find the speed (in m s−1) of the centre of the sphere at the given instant.Correct answer is '1'. Can you explain this answer?, a detailed solution for A sphere of mass MM and radius R rests on two supports of the same height. One support is stationary while the other is moving with a velocity v = √2 m s−1 (see in the diagram). Assume the stationary support is rough and the moving support is frictionless so that the sphere is slipping at B. At the instant shown, AB = R√2=R2. Find the speed (in m s−1) of the centre of the sphere at the given instant.Correct answer is '1'. Can you explain this answer? has been provided alongside types of A sphere of mass MM and radius R rests on two supports of the same height. One support is stationary while the other is moving with a velocity v = √2 m s−1 (see in the diagram). Assume the stationary support is rough and the moving support is frictionless so that the sphere is slipping at B. At the instant shown, AB = R√2=R2. Find the speed (in m s−1) of the centre of the sphere at the given instant.Correct answer is '1'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A sphere of mass MM and radius R rests on two supports of the same height. One support is stationary while the other is moving with a velocity v = √2 m s−1 (see in the diagram). Assume the stationary support is rough and the moving support is frictionless so that the sphere is slipping at B. At the instant shown, AB = R√2=R2. Find the speed (in m s−1) of the centre of the sphere at the given instant.Correct answer is '1'. Can you explain this answer? tests, examples and also practice JEE tests.
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