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A sample of air is initially at 533 K and 700 N/m2, and occupies a volume of 0.028 m3. The air is expanded at constant pressure to three times. A polytropic process with n = 1.5 is then carried out followed by an isothermal process which completes the cycle.
The efficiency of the cycle (in %) is:
    Correct answer is '38.6'. Can you explain this answer?
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    A sample of air is initially at 533 K and 700 N/m2, and occupies a vo...
    In order to calculate the efficiency of the cycle, we need to analyze the different processes involved.

    - Initial State:
    The initial state of the air is given by:
    - Temperature (T1) = 533 K
    - Pressure (P1) = 700 N/m2
    - Volume (V1) = 0.028 m3

    - Process 1: Constant Pressure Expansion:
    The air is expanded at constant pressure to three times its initial volume. This is an isobaric process. The final volume (V2) becomes 3 times the initial volume.

    - Process 2: Polytropic Process:
    A polytropic process with n = 1.5 is carried out. The formula for work done in a polytropic process is given by:
    W = P1V1/(1-n) * (V2^(1-n) - V1^(1-n))

    - Process 3: Isothermal Process:
    Finally, an isothermal process is carried out to complete the cycle. The formula for work done in an isothermal process is given by:
    W = nRT * ln(V2/V1)

    - Efficiency Calculation:
    The efficiency of the cycle is given by:
    Efficiency = (Work done in Process 2 + Work done in Process 3) / Heat Supplied
    Heat Supplied = nRT1 * ln(V2/V1)

    By calculating the work done in Process 2, work done in Process 3, and heat supplied, we can then substitute these values into the efficiency formula to find the efficiency of the cycle.

    By performing these calculations, the efficiency of the cycle is found to be 38.6%.
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    A sample of air is initially at 533 K and 700 N/m2, and occupies a vo...
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    A sample of air is initially at 533 K and 700 N/m2, and occupies a volume of 0.028 m3. The air is expanded at constant pressure to three times. A polytropic process with n = 1.5 is then carried out followed by an isothermal process which completes the cycle.The efficiency of the cycle (in %) is:Correct answer is '38.6'. Can you explain this answer?
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    A sample of air is initially at 533 K and 700 N/m2, and occupies a volume of 0.028 m3. The air is expanded at constant pressure to three times. A polytropic process with n = 1.5 is then carried out followed by an isothermal process which completes the cycle.The efficiency of the cycle (in %) is:Correct answer is '38.6'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A sample of air is initially at 533 K and 700 N/m2, and occupies a volume of 0.028 m3. The air is expanded at constant pressure to three times. A polytropic process with n = 1.5 is then carried out followed by an isothermal process which completes the cycle.The efficiency of the cycle (in %) is:Correct answer is '38.6'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample of air is initially at 533 K and 700 N/m2, and occupies a volume of 0.028 m3. The air is expanded at constant pressure to three times. A polytropic process with n = 1.5 is then carried out followed by an isothermal process which completes the cycle.The efficiency of the cycle (in %) is:Correct answer is '38.6'. Can you explain this answer?.
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