A (-6,3) be a point on the graph . Draw AL is perpendicular to x-axis ...
In order for a line to be perpendicular to the x-axis, it must have a slope of zero. The slope of a line can be found using the formula: slope = (change in y) / (change in x). In this case, since the point A is on the x-axis, the change in y is zero, making the slope zero.
A line that has a slope of zero is parallel to the x-axis, so it will have the same x-coordinate as point A, which is -6. The y-coordinate of point L can be any value, since the line is parallel to the x-axis.
So the coordinates of point L are (-6, y) where y can be any value.
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A (-6,3) be a point on the graph . Draw AL is perpendicular to x-axis ...
Graph of the Point (-6,3)
To begin with, let's plot the point (-6,3) on the coordinate plane. The x-coordinate of the point is -6, which means it lies 6 units to the left of the origin (0,0). The y-coordinate of the point is 3, which means it lies 3 units above the x-axis.
Now, let's draw the line AL perpendicular to the x-axis passing through the point (-6,3).
Drawing the Perpendicular Line AL
To draw a line perpendicular to the x-axis passing through (-6,3), we need to understand that a line perpendicular to the x-axis is a vertical line.
Since the line AL is vertical, it will have the same x-coordinate as the point (-6,3). Therefore, the x-coordinate of point L will also be -6.
The y-coordinate of point L can be any value since it lies on a vertical line. However, to maintain consistency with the given point (-6,3), the y-coordinate of point L will also be 3.
Hence, the coordinates of point L are (-6,3).
Summary
- The point (-6,3) is plotted on the graph at 6 units to the left of the origin and 3 units above the x-axis.
- To draw a line perpendicular to the x-axis passing through (-6,3), we find that point L will have the same x-coordinate of -6 and the same y-coordinate of 3.
- Therefore, the coordinates of point L are (-6,3).
A (-6,3) be a point on the graph . Draw AL is perpendicular to x-axis ...
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