All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >   Assume that you are using an open-end manome... Start Learning for Free
SaveJoin the Discussion on the App
Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)
(Round off up to 1 decimal place)
    Correct answer is '731.7'. Can you explain this answer?
    FREE This question is part of
    Download PDF Attempt Test
    		Download PDF Attempt this Test
    Most Upvoted Answer
    Assume that you are using an open-end manometer filled with mineral o...
    The gas pressure in the bulb equals the difference between the outside pressure and the manometer reading. The manometer indicates that the pressure of the gas in the bulb is less than the atmospheric pressure because the liquid level is higher on the side connected to the sample.
    Mercury is more dense than mineral oil by a factor of
    A given pressure will hold a column of mercury only 1/16.5 times the height of a column of mineral oil.
    Free Test
    FREE
    Start Free Test
    		Start Free Test
    Community Answer
    Assume that you are using an open-end manometer filled with mineral o...
    Given:
    - The height difference between the arm connected to the bulb and the arm connected to the atmosphere is 237 mm.
    - The atmospheric pressure is 746 mm Hg.
    - The density of mercury is 13.6 g/ml.
    - The density of mineral oil is 0.822 g/ml.

    To Find:
    - The gas pressure in the bulb in millimeters of Hg.

    Assumptions:
    - The density of mineral oil remains constant throughout the calculation.
    - The manometer is open at one end and connected to the bulb at the other end.

    Formula:
    - The pressure difference between the two arms of the manometer is given by the equation:
    ΔP = ρgh
    where ρ is the density of the fluid (mineral oil), g is the acceleration due to gravity, and h is the height difference between the two arms.

    Calculation:
    Given:
    - Height difference between the arms of the manometer = 237 mm.
    - Atmospheric pressure = 746 mm Hg.
    - Density of mineral oil = 0.822 g/ml.

    Step 1: Convert the height difference from millimeters to centimeters:
    - Height difference = 237 mm = 23.7 cm.

    Step 2: Calculate the pressure difference between the two arms of the manometer:
    - ΔP = ρgh
    - ΔP = (0.822 g/ml) * (9.8 m/s^2) * (23.7 cm)
    - ΔP = 0.822 * 9.8 * 23.7 * 10^-3 atm
    - ΔP = 0.191 atm.

    Step 3: Convert the pressure difference from atm to millimeters of Hg:
    - 1 atm = 760 mm Hg.
    - ΔP = 0.191 atm * 760 mm Hg/atm
    - ΔP = 145.16 mm Hg.

    Step 4: Calculate the gas pressure in the bulb:
    - The pressure in the bulb is equal to the atmospheric pressure minus the pressure difference:
    - Gas pressure in the bulb = Atmospheric pressure - Pressure difference
    - Gas pressure in the bulb = 746 mm Hg - 145.16 mm Hg
    - Gas pressure in the bulb = 600.84 mm Hg.

    Answer:
    The gas pressure in the bulb is 600.8 mm Hg.
    < Previous Question Next Question >
    Explore Courses for JEE exam

    Similar JEE Doubts

    The atmospheric lapse rateFor small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantityTP(1 – λ)/λ has a uniform value through the layers of troposphere.(M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)Q. If behaviour of the mixing of parcels of air is approximately assumed to be adiabatic then lapse rate can be expressed as

    The atmospheric lapse rateFor small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantityTP(1 – λ)/λ has a uniform value through the layers of troposphere.(M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)Q. The value of theoretical lapse rate on the earth is (use g = 9.8 m/s2 ; R = 8.3 J/mol-k and M = 29 g/mol)

    The atmospheric lapse rateFor small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantityTP(1 – λ)/λ has a uniform value through the layers of troposphere.(M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)Q. Mechanical equilibrium of the atmosphere requires that the pressure decreases with altitude according to . Assuming free fall acceleration to be uniform, then lapse rate is given by

    Top Courses for JEEView all

    Top Courses for JEE

    Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer?
    Question Description
    Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer?.
    Solutions for Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
    Here you can find the meaning of Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer?, a detailed solution for Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? has been provided alongside types of Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? tests, examples and also practice JEE tests.
    Explore Courses for JEE exam

    Top Courses for JEE

    Explore Courses

    Suggested Free Tests

    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev
    Get App
    © EduRev
    Education Revolution
    Signup to see your scores go up within 7 days!
    Access 1000+ FREE Docs, Videos and Tests
    Takes less than 10 seconds to signup