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Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)
(Round off up to 1 decimal place)
Correct answer is '731.7'. Can you explain this answer?
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Assume that you are using an open-end manometer filled with mineral o...
The gas pressure in the bulb equals the difference between the outside pressure and the manometer reading. The manometer indicates that the pressure of the gas in the bulb is less than the atmospheric pressure because the liquid level is higher on the side connected to the sample.
Mercury is more dense than mineral oil by a factor of 
A given pressure will hold a column of mercury only 1/16.5 times the height of a column of mineral oil.
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Assume that you are using an open-end manometer filled with mineral o...
Given:
- The height difference between the arm connected to the bulb and the arm connected to the atmosphere is 237 mm.
- The atmospheric pressure is 746 mm Hg.
- The density of mercury is 13.6 g/ml.
- The density of mineral oil is 0.822 g/ml.
To Find:
- The gas pressure in the bulb in millimeters of Hg.
Assumptions:
- The density of mineral oil remains constant throughout the calculation.
- The manometer is open at one end and connected to the bulb at the other end.
Formula:
- The pressure difference between the two arms of the manometer is given by the equation:
ΔP = ρgh
where ρ is the density of the fluid (mineral oil), g is the acceleration due to gravity, and h is the height difference between the two arms.
Calculation:
Given:
- Height difference between the arms of the manometer = 237 mm.
- Atmospheric pressure = 746 mm Hg.
- Density of mineral oil = 0.822 g/ml.
Step 1: Convert the height difference from millimeters to centimeters:
- Height difference = 237 mm = 23.7 cm.
Step 2: Calculate the pressure difference between the two arms of the manometer:
- ΔP = ρgh
- ΔP = (0.822 g/ml) * (9.8 m/s^2) * (23.7 cm)
- ΔP = 0.822 * 9.8 * 23.7 * 10^-3 atm
- ΔP = 0.191 atm.
Step 3: Convert the pressure difference from atm to millimeters of Hg:
- 1 atm = 760 mm Hg.
- ΔP = 0.191 atm * 760 mm Hg/atm
- ΔP = 145.16 mm Hg.
Step 4: Calculate the gas pressure in the bulb:
- The pressure in the bulb is equal to the atmospheric pressure minus the pressure difference:
- Gas pressure in the bulb = Atmospheric pressure - Pressure difference
- Gas pressure in the bulb = 746 mm Hg - 145.16 mm Hg
- Gas pressure in the bulb = 600.84 mm Hg.
Answer:
The gas pressure in the bulb is 600.8 mm Hg.
- The height difference between the arm connected to the bulb and the arm connected to the atmosphere is 237 mm.
- The atmospheric pressure is 746 mm Hg.
- The density of mercury is 13.6 g/ml.
- The density of mineral oil is 0.822 g/ml.
To Find:
- The gas pressure in the bulb in millimeters of Hg.
Assumptions:
- The density of mineral oil remains constant throughout the calculation.
- The manometer is open at one end and connected to the bulb at the other end.
Formula:
- The pressure difference between the two arms of the manometer is given by the equation:
ΔP = ρgh
where ρ is the density of the fluid (mineral oil), g is the acceleration due to gravity, and h is the height difference between the two arms.
Calculation:
Given:
- Height difference between the arms of the manometer = 237 mm.
- Atmospheric pressure = 746 mm Hg.
- Density of mineral oil = 0.822 g/ml.
Step 1: Convert the height difference from millimeters to centimeters:
- Height difference = 237 mm = 23.7 cm.
Step 2: Calculate the pressure difference between the two arms of the manometer:
- ΔP = ρgh
- ΔP = (0.822 g/ml) * (9.8 m/s^2) * (23.7 cm)
- ΔP = 0.822 * 9.8 * 23.7 * 10^-3 atm
- ΔP = 0.191 atm.
Step 3: Convert the pressure difference from atm to millimeters of Hg:
- 1 atm = 760 mm Hg.
- ΔP = 0.191 atm * 760 mm Hg/atm
- ΔP = 145.16 mm Hg.
Step 4: Calculate the gas pressure in the bulb:
- The pressure in the bulb is equal to the atmospheric pressure minus the pressure difference:
- Gas pressure in the bulb = Atmospheric pressure - Pressure difference
- Gas pressure in the bulb = 746 mm Hg - 145.16 mm Hg
- Gas pressure in the bulb = 600.84 mm Hg.
Answer:
The gas pressure in the bulb is 600.8 mm Hg.
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Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer?
Question Description
Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer?.
Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer?.
Solutions for Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer?, a detailed solution for Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? has been provided alongside types of Assume that you are using an open-end manometer filled with mineral oil rather than mercury. What is the gas pressure in the bulb (in millimetre of Hg) if the level of mineral oil in the arm connected to the bulb is 237 mm higher than the level in the arm connected to the atmosphere and the atmospheric pressure is 746 mm Hg? (The density of mercury is 13.6 g/ml and that of mineral oil is 0.822 g/ml.)(Round off up to 1 decimal place)Correct answer is '731.7'. Can you explain this answer? theory, EduRev gives you an
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