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A disc of radius R rotating with an angular velocity ω0 is placed on a rough horizontal surface. If initial velocity of centre of disc is zero, then velocity of centre of disc when it ceases to slip, comes out to be ω0R/k, value of k is _____.
    Correct answer is '3'. Can you explain this answer?
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    A disc of radius R rotating with an angular velocity ω0 is placed on ...
    Let v be the velocity of centre of mass of disc.
    Condition for pure rolling i.e., when slip ceases is v = Rω
    From conservation of angular momentum,
    Hence, the value of k = 3.
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    A disc of radius R rotating with an angular velocity ω0 is placed on a rough horizontal surface. If initial velocity of centre of disc is zero, then velocity of centre of disc when it ceases to slip, comes out to be ω0R/k, value of k is _____.Correct answer is '3'. Can you explain this answer?
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    A disc of radius R rotating with an angular velocity ω0 is placed on a rough horizontal surface. If initial velocity of centre of disc is zero, then velocity of centre of disc when it ceases to slip, comes out to be ω0R/k, value of k is _____.Correct answer is '3'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A disc of radius R rotating with an angular velocity ω0 is placed on a rough horizontal surface. If initial velocity of centre of disc is zero, then velocity of centre of disc when it ceases to slip, comes out to be ω0R/k, value of k is _____.Correct answer is '3'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A disc of radius R rotating with an angular velocity ω0 is placed on a rough horizontal surface. If initial velocity of centre of disc is zero, then velocity of centre of disc when it ceases to slip, comes out to be ω0R/k, value of k is _____.Correct answer is '3'. Can you explain this answer?.
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