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Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only ifa)dA Fb)dB > dFc)dA > dFd)dA + dB = 2dFCorrect answer is option 'A,B,D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only ifa)dA Fb)dB > dFc)dA > dFd)dA + dB = 2dFCorrect answer is option 'A,B,D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only ifa)dA Fb)dB > dFc)dA > dFd)dA + dB = 2dFCorrect answer is option 'A,B,D'. Can you explain this answer?.

Solutions for Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only ifa)dA Fb)dB > dFc)dA > dFd)dA + dB = 2dFCorrect answer is option 'A,B,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only ifa)dA Fb)dB > dFc)dA > dFd)dA + dB = 2dFCorrect answer is option 'A,B,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only ifa)dA Fb)dB > dFc)dA > dFd)dA + dB = 2dFCorrect answer is option 'A,B,D'. Can you explain this answer?, a detailed solution for Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only ifa)dA Fb)dB > dFc)dA > dFd)dA + dB = 2dFCorrect answer is option 'A,B,D'. Can you explain this answer? has been provided alongside types of Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only ifa)dA Fb)dB > dFc)dA > dFd)dA + dB = 2dFCorrect answer is option 'A,B,D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only ifa)dA Fb)dB > dFc)dA > dFd)dA + dB = 2dFCorrect answer is option 'A,B,D'. Can you explain this answer? tests, examples and also practice JEE tests.