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An aircraft is flying in level flight at a speed of 200 km/hr through air (Density, ρ = 1.2 kg/m3 and viscosity, m = 1.6 × 10-5 N-s/m2). The lift co-efficient at this speed is 0.4 and the drag co-efficient is 0.0065. The mass of the aircraft is 800 kg. The effective lift area (in m2) of the aircraft is
(Answer up to one decimal place)
    Correct answer is '10.6'. Can you explain this answer?
    Most Upvoted Answer
    An aircraft is flying in level flight at a speed of 200 km/hr through ...
    Aircraft generates the lift equal to the weight of the aircraft, so at the equilibrium condition.
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    Community Answer
    An aircraft is flying in level flight at a speed of 200 km/hr through ...
    Given Data:
    - Speed of aircraft (V) = 200 km/hr = 55.56 m/s
    - Density of air (ρ) = 1.2 kg/m3
    - Viscosity of air (m) = 1.6 x 10^-5 N-s/m^2
    - Lift coefficient (CL) = 0.4
    - Drag coefficient (CD) = 0.0065
    - Mass of aircraft (m) = 800 kg

    Calculations:
    1. Lift force (L) = 0.5 x ρ x V^2 x CL x A
    2. Drag force (D) = 0.5 x ρ x V^2 x CD x A
    3. Weight of the aircraft (W) = m x g

    Equating Lift and Weight:
    - L = W
    - 0.5 x ρ x V^2 x CL x A = m x g
    - A = (m x g) / (0.5 x ρ x V^2 x CL)
    - A = (800 x 9.81) / (0.5 x 1.2 x 55.56^2 x 0.4)
    - A = 10.6 m^2
    Therefore, the effective lift area of the aircraft is 10.6 m^2.
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    An aircraft is flying in level flight at a speed of 200 km/hr through air (Density, ρ = 1.2 kg/m3 and viscosity, m = 1.6 × 10-5 N-s/m2). The lift co-efficient at this speed is 0.4 and the drag co-efficient is 0.0065. The mass of the aircraft is 800 kg. The effective lift area (in m2) of the aircraft is(Answer up to one decimal place)Correct answer is '10.6'. Can you explain this answer?
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    An aircraft is flying in level flight at a speed of 200 km/hr through air (Density, ρ = 1.2 kg/m3 and viscosity, m = 1.6 × 10-5 N-s/m2). The lift co-efficient at this speed is 0.4 and the drag co-efficient is 0.0065. The mass of the aircraft is 800 kg. The effective lift area (in m2) of the aircraft is(Answer up to one decimal place)Correct answer is '10.6'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about An aircraft is flying in level flight at a speed of 200 km/hr through air (Density, ρ = 1.2 kg/m3 and viscosity, m = 1.6 × 10-5 N-s/m2). The lift co-efficient at this speed is 0.4 and the drag co-efficient is 0.0065. The mass of the aircraft is 800 kg. The effective lift area (in m2) of the aircraft is(Answer up to one decimal place)Correct answer is '10.6'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aircraft is flying in level flight at a speed of 200 km/hr through air (Density, ρ = 1.2 kg/m3 and viscosity, m = 1.6 × 10-5 N-s/m2). The lift co-efficient at this speed is 0.4 and the drag co-efficient is 0.0065. The mass of the aircraft is 800 kg. The effective lift area (in m2) of the aircraft is(Answer up to one decimal place)Correct answer is '10.6'. Can you explain this answer?.
    Solutions for An aircraft is flying in level flight at a speed of 200 km/hr through air (Density, ρ = 1.2 kg/m3 and viscosity, m = 1.6 × 10-5 N-s/m2). The lift co-efficient at this speed is 0.4 and the drag co-efficient is 0.0065. The mass of the aircraft is 800 kg. The effective lift area (in m2) of the aircraft is(Answer up to one decimal place)Correct answer is '10.6'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
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