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If xexy = y + sin2⁡x, then at x = 0, dy/dx:
    Correct answer is '1'. Can you explain this answer?
    Most Upvoted Answer
    If xexy= y + sin2x, then atx = 0, dy/dx:Correct answer is '1'. Can you...
    Given,
    xexy = y + sin2⁡x
    We know that,
    ⇒ xexy = y + sin2⁡x      [x=0]
    ⇒ 0 × e= y + sin2⁡0
    ⇒ 0 = y + 0
    ⇒ y = 0
    If f and g are both differentiable, then
    Differentiating with respect to x, we get
    = 1
    Hence, the correct answer is 1.
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    If xexy= y + sin2x, then atx = 0, dy/dx:Correct answer is '1'. Can you explain this answer?
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