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Directions: The question has four choices, out of which ONE or MORE may be correct.


A composite block is made of slabs A, B, C, D and E of different thermal conductivities (given in terms of a constant K) and sizes (given in terms of length, L) as shown in the figure. All slabs are of same width. Heat 'Q' flows only from left to right through the blocks. Then in steady state,


  • a)
    heat flow through A and E slabs is same

  • b)
    heat flow through slab E is maximum

  • c)
    temperature difference across slab E is smallest

  • d)
    heat flow through C = heat flow through B + heat flow through D

Correct answer is option 'A,C,D'. Can you explain this answer?
Most Upvoted Answer
Directions: The question has four choices, out of which ONE or MORE ma...
Using Fourier law,
Q = UA△T
QA = 2K/L
QB = 3K/4L
QC = K/L
QD = 5K/4L
QE = 6K/L
Also, heat flow across the system remains same.
∴ Option 1 is correct.
And since UE is maximum and heat flow across the system remains constant, option 3 is also correct.
Now,
∵ UC = K\L
∴ QC = KA△T/L
Also,
∵ UB + D = 5K/4L + 3K/4L + 4K/L
∴ QB + D = KA△T/L
∴ QC = QB + D
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Directions: The question has four choices, out of which ONE or MORE may be correct.A composite block is made of slabs A, B, C, D and E of different thermal conductivities (given in terms of a constant K) and sizes (given in terms of length, L) as shown in the figure. All slabs are of same width. Heat Q flows only from left to right through the blocks. Then in steady state,a)heat flow through A and E slabs is sameb)heat flow through slab E is maximumc)temperature difference across slab E is smallestd)heat flow through C = heat flow through B + heat flow through DCorrect answer is option 'A,C,D'. Can you explain this answer?
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Directions: The question has four choices, out of which ONE or MORE may be correct.A composite block is made of slabs A, B, C, D and E of different thermal conductivities (given in terms of a constant K) and sizes (given in terms of length, L) as shown in the figure. All slabs are of same width. Heat Q flows only from left to right through the blocks. Then in steady state,a)heat flow through A and E slabs is sameb)heat flow through slab E is maximumc)temperature difference across slab E is smallestd)heat flow through C = heat flow through B + heat flow through DCorrect answer is option 'A,C,D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Directions: The question has four choices, out of which ONE or MORE may be correct.A composite block is made of slabs A, B, C, D and E of different thermal conductivities (given in terms of a constant K) and sizes (given in terms of length, L) as shown in the figure. All slabs are of same width. Heat Q flows only from left to right through the blocks. Then in steady state,a)heat flow through A and E slabs is sameb)heat flow through slab E is maximumc)temperature difference across slab E is smallestd)heat flow through C = heat flow through B + heat flow through DCorrect answer is option 'A,C,D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions: The question has four choices, out of which ONE or MORE may be correct.A composite block is made of slabs A, B, C, D and E of different thermal conductivities (given in terms of a constant K) and sizes (given in terms of length, L) as shown in the figure. All slabs are of same width. Heat Q flows only from left to right through the blocks. Then in steady state,a)heat flow through A and E slabs is sameb)heat flow through slab E is maximumc)temperature difference across slab E is smallestd)heat flow through C = heat flow through B + heat flow through DCorrect answer is option 'A,C,D'. Can you explain this answer?.
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