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If the total number of faradays required to oxidize the following separately:
a. one mole of S2O32- in acid medium
b. one Equivalent of S2O32- in neutral medium
c. one mole of S2O32- in basic medium.
is 10 K. Then the value of 'K' is ____
    Correct answer is '1'. Can you explain this answer?
    Most Upvoted Answer
    If the total number of faradays required to oxidize the following sep...
    Total Faradays in (i), (ii) and (iii) = 1 + 1 + 8 = 10 F
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    Community Answer
    If the total number of faradays required to oxidize the following sep...
    Total Faradays in (i), (ii) and (iii) = 1 + 1 + 8 = 10 F
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    Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seam ctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine.Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates.Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water= 18 g). Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule.0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.Which of the following solutions, when mixed with 100 ml of 0.05 M NaOH, will give a neutral solution?

    Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seam ctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine.Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates.Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water= 18 g). Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule.0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.How many gram of phosphoric acid (H3PO4) would be required to neutralize 58 g of magnesium hydroxide?

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    If the total number of faradays required to oxidize the following separately:a. one mole of S2O32- in acid mediumb. one Equivalent of S2O32- in neutral mediumc. one mole of S2O32- in basic medium.is 10 K. Then the value of 'K' is ____Correct answer is '1'. Can you explain this answer?
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    If the total number of faradays required to oxidize the following separately:a. one mole of S2O32- in acid mediumb. one Equivalent of S2O32- in neutral mediumc. one mole of S2O32- in basic medium.is 10 K. Then the value of 'K' is ____Correct answer is '1'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If the total number of faradays required to oxidize the following separately:a. one mole of S2O32- in acid mediumb. one Equivalent of S2O32- in neutral mediumc. one mole of S2O32- in basic medium.is 10 K. Then the value of 'K' is ____Correct answer is '1'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the total number of faradays required to oxidize the following separately:a. one mole of S2O32- in acid mediumb. one Equivalent of S2O32- in neutral mediumc. one mole of S2O32- in basic medium.is 10 K. Then the value of 'K' is ____Correct answer is '1'. Can you explain this answer?.
    Solutions for If the total number of faradays required to oxidize the following separately:a. one mole of S2O32- in acid mediumb. one Equivalent of S2O32- in neutral mediumc. one mole of S2O32- in basic medium.is 10 K. Then the value of 'K' is ____Correct answer is '1'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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