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If the switch angle is 75°, diamond angle is 45° and radius of slip is 38 m, then the distance between the point slip and the nose of obtuse crossing is __________ m. (Answer up to two decimal places)
    Correct answer is '24.42'. Can you explain this answer?
    Most Upvoted Answer
    If the switch angle is 75°, diamond angle is 45° and radius of slip i...
    The distance between the point slip and the nose of the obtuse crossing can be determined using the given switch angle, diamond angle, and radius of slip. Let's break down the solution into steps:

    Step 1: Understanding the problem
    - The switch angle is the angle between the diverging track and the straight track.
    - The diamond angle is the angle between the straight track and the crossing diamond.
    - The radius of slip is the radius of the curve formed by the diverging track.

    Step 2: Calculate the tangent angle
    - The tangent angle is the angle formed between the diverging track and the radius of slip.
    - It can be calculated using the formula: tangent angle = switch angle - diamond angle.
    - Substituting the given values, tangent angle = 75° - 45° = 30°.

    Step 3: Calculate the distance between the slip and the obtuse crossing
    - The distance between the slip and the obtuse crossing can be calculated using the formula: distance = radius of slip * tan(tangent angle).
    - Substituting the given values, distance = 38 m * tan(30°).
    - Using a scientific calculator, tan(30°) is approximately 0.57735.
    - Therefore, distance = 38 m * 0.57735 ≈ 21.92 m.

    Step 4: Calculate the distance between the slip and the nose of the obtuse crossing
    - The distance between the slip and the nose of the obtuse crossing can be calculated by subtracting the distance between the slip and the obtuse crossing from the radius of slip.
    - Distance between the slip and the nose of the obtuse crossing = radius of slip - distance.
    - Substituting the calculated value, distance = 38 m - 21.92 m ≈ 16.08 m.

    Step 5: Convert the distance to two decimal places
    - Rounding off the distance to two decimal places, the final answer is approximately 16.08 m ≈ 16.09 m.

    Therefore, the distance between the point slip and the nose of the obtuse crossing is approximately 16.09 m.
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    Community Answer
    If the switch angle is 75°, diamond angle is 45° and radius of slip i...
    Given: S = 75o, ∝ = 45o and r = 38 m
    Distance between point slip and the nose of obtuse crossing is
    = 24.42 m
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    If the switch angle is 75°, diamond angle is 45° and radius of slip is 38 m, then the distance between the point slip and the nose of obtuse crossing is __________ m. (Answer up to two decimal places)Correct answer is '24.42'. Can you explain this answer?
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    If the switch angle is 75°, diamond angle is 45° and radius of slip is 38 m, then the distance between the point slip and the nose of obtuse crossing is __________ m. (Answer up to two decimal places)Correct answer is '24.42'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about If the switch angle is 75°, diamond angle is 45° and radius of slip is 38 m, then the distance between the point slip and the nose of obtuse crossing is __________ m. (Answer up to two decimal places)Correct answer is '24.42'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the switch angle is 75°, diamond angle is 45° and radius of slip is 38 m, then the distance between the point slip and the nose of obtuse crossing is __________ m. (Answer up to two decimal places)Correct answer is '24.42'. Can you explain this answer?.
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