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A uniform rectangular rod having the cross-section of 0.17 m x 0.31 m is shown in figure:
The specific weight of the rectangular rod in kN/m3 will be ___.
(Rounded off to two decimal places)
Correct answer is '6.28'. Can you explain this answer?
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A uniform rectangular rod having the cross-section of 0.17 m x 0.31 m...
The FBD of the rod is shown below
Weight of the rectangular rod
W = γ x v
= γ x (0.17 x 0.31 x 10) = 0.527γ ……….(i)
where γ = specific weight of the rod.
The Buoyancy force,
Taking the moment about O,
Substitute the values of W & FB from equation (i) & (ii), we get
0.521γ x 5 = 0.422 x 9.81 x 4
γ ≃ 6.28 kN/m3
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A uniform rectangular rod having the cross-section of 0.17 m x 0.31 m is shown in figure:The specific weight of the rectangular rod in kN/m3 will be ___.(Rounded off to two decimal places)Correct answer is '6.28'. Can you explain this answer?
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