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A rectangular steel plate with thickness t = 10 mm is subjected to a uniform normal stresses σx and σy as shown in the figure. Strain gauges A and B oriented in the x and y directions, respectively, are attached to the plate. The gauge readings are εx = 480 x 10-6 (elongation) and εy = 130 x 10-6 (elongation). What will be the stresses σx and σy and the change in the thickness t of the plate? (Take E = 200 GPa, v = 0.30)a)σx = 6.02 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmb)σx = 114.1 MPa, σy = 60.2 MPa, t = 2610 x 10−6 mmc)σx = 60.2 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmd)σx = 114.1 MPa, σy = 60.2 MPa, t = − 2610 x 10−6 mmCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A rectangular steel plate with thickness t = 10 mm is subjected to a uniform normal stresses σx and σy as shown in the figure. Strain gauges A and B oriented in the x and y directions, respectively, are attached to the plate. The gauge readings are εx = 480 x 10-6 (elongation) and εy = 130 x 10-6 (elongation). What will be the stresses σx and σy and the change in the thickness t of the plate? (Take E = 200 GPa, v = 0.30)a)σx = 6.02 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmb)σx = 114.1 MPa, σy = 60.2 MPa, t = 2610 x 10−6 mmc)σx = 60.2 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmd)σx = 114.1 MPa, σy = 60.2 MPa, t = − 2610 x 10−6 mmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular steel plate with thickness t = 10 mm is subjected to a uniform normal stresses σx and σy as shown in the figure. Strain gauges A and B oriented in the x and y directions, respectively, are attached to the plate. The gauge readings are εx = 480 x 10-6 (elongation) and εy = 130 x 10-6 (elongation). What will be the stresses σx and σy and the change in the thickness t of the plate? (Take E = 200 GPa, v = 0.30)a)σx = 6.02 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmb)σx = 114.1 MPa, σy = 60.2 MPa, t = 2610 x 10−6 mmc)σx = 60.2 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmd)σx = 114.1 MPa, σy = 60.2 MPa, t = − 2610 x 10−6 mmCorrect answer is option 'D'. Can you explain this answer?.

Solutions for A rectangular steel plate with thickness t = 10 mm is subjected to a uniform normal stresses σx and σy as shown in the figure. Strain gauges A and B oriented in the x and y directions, respectively, are attached to the plate. The gauge readings are εx = 480 x 10-6 (elongation) and εy = 130 x 10-6 (elongation). What will be the stresses σx and σy and the change in the thickness t of the plate? (Take E = 200 GPa, v = 0.30)a)σx = 6.02 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmb)σx = 114.1 MPa, σy = 60.2 MPa, t = 2610 x 10−6 mmc)σx = 60.2 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmd)σx = 114.1 MPa, σy = 60.2 MPa, t = − 2610 x 10−6 mmCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.

Here you can find the meaning of A rectangular steel plate with thickness t = 10 mm is subjected to a uniform normal stresses σx and σy as shown in the figure. Strain gauges A and B oriented in the x and y directions, respectively, are attached to the plate. The gauge readings are εx = 480 x 10-6 (elongation) and εy = 130 x 10-6 (elongation). What will be the stresses σx and σy and the change in the thickness t of the plate? (Take E = 200 GPa, v = 0.30)a)σx = 6.02 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmb)σx = 114.1 MPa, σy = 60.2 MPa, t = 2610 x 10−6 mmc)σx = 60.2 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmd)σx = 114.1 MPa, σy = 60.2 MPa, t = − 2610 x 10−6 mmCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A rectangular steel plate with thickness t = 10 mm is subjected to a uniform normal stresses σx and σy as shown in the figure. Strain gauges A and B oriented in the x and y directions, respectively, are attached to the plate. The gauge readings are εx = 480 x 10-6 (elongation) and εy = 130 x 10-6 (elongation). What will be the stresses σx and σy and the change in the thickness t of the plate? (Take E = 200 GPa, v = 0.30)a)σx = 6.02 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmb)σx = 114.1 MPa, σy = 60.2 MPa, t = 2610 x 10−6 mmc)σx = 60.2 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmd)σx = 114.1 MPa, σy = 60.2 MPa, t = − 2610 x 10−6 mmCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A rectangular steel plate with thickness t = 10 mm is subjected to a uniform normal stresses σx and σy as shown in the figure. Strain gauges A and B oriented in the x and y directions, respectively, are attached to the plate. The gauge readings are εx = 480 x 10-6 (elongation) and εy = 130 x 10-6 (elongation). What will be the stresses σx and σy and the change in the thickness t of the plate? (Take E = 200 GPa, v = 0.30)a)σx = 6.02 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmb)σx = 114.1 MPa, σy = 60.2 MPa, t = 2610 x 10−6 mmc)σx = 60.2 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmd)σx = 114.1 MPa, σy = 60.2 MPa, t = − 2610 x 10−6 mmCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A rectangular steel plate with thickness t = 10 mm is subjected to a uniform normal stresses σx and σy as shown in the figure. Strain gauges A and B oriented in the x and y directions, respectively, are attached to the plate. The gauge readings are εx = 480 x 10-6 (elongation) and εy = 130 x 10-6 (elongation). What will be the stresses σx and σy and the change in the thickness t of the plate? (Take E = 200 GPa, v = 0.30)a)σx = 6.02 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmb)σx = 114.1 MPa, σy = 60.2 MPa, t = 2610 x 10−6 mmc)σx = 60.2 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmd)σx = 114.1 MPa, σy = 60.2 MPa, t = − 2610 x 10−6 mmCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A rectangular steel plate with thickness t = 10 mm is subjected to a uniform normal stresses σx and σy as shown in the figure. Strain gauges A and B oriented in the x and y directions, respectively, are attached to the plate. The gauge readings are εx = 480 x 10-6 (elongation) and εy = 130 x 10-6 (elongation). What will be the stresses σx and σy and the change in the thickness t of the plate? (Take E = 200 GPa, v = 0.30)a)σx = 6.02 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmb)σx = 114.1 MPa, σy = 60.2 MPa, t = 2610 x 10−6 mmc)σx = 60.2 MPa, σy = 114.1 MPa, t = 2610 x 10−6 mmd)σx = 114.1 MPa, σy = 60.2 MPa, t = − 2610 x 10−6 mmCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.