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Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.
26.035 = VT0.13f 0.77d0.37
A 100 min. tool life was obtained under the following cutting conditions:
Velocity = 25 m/min
Feed = 0.3125 mm/rev
Diameter of bar = 2.50 mm
Q. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?
- a)25 min, 59.25 min, 34.23 min
- b)34.23 min, 25 min, 59.25 min
- c)25 min, 34.23 min, 59.25 min
- d)59.25 min, 34.23 min, 25 min
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
Directions: The work-tool system is governed by the following equation...
We have V = 25 m/min, f = 0.3125 mm/rev, d = 2.50 mm, T = 100 min,
C = 26.035, n = 0.13
Case I:
V is increased by 20%, feed and diameter of the bar remains constant.
Substituting the values in the Taylor's equation (VTn = C), we have
V(100)0.13 = 26.035 . ..(i)
Also with 20% increase in velocity, we can write
1.2V (T)0.13 = 26.035 ...(ii)
From equations (i) and (ii), we have
or T = 25 min
Case II:
When feed is increased by 20%, V and d are constant, we have
(100)0.13 x (f)0.77 = 26.035 ….. (iii)
With 20% increase in feed, we can write
(T)0.13 x (1.2f)0.77 = 26.035 ……(iv)
From equations. (iii) and (iv), we have
Or T = 34.23 min
Case III:
When depth of cut is increased by 20%, V and feed rate are constant, we have
(100)0.13 x (d)0.37 = 26.035……(V)
With 20% increase in feed, we can write
(T)0.13 x (1.2d)0.37 = 26.035 …….(vi)
From equations (v) and (vi), we have
(T)0.13 = (100)0.13/( 1.2)0.37 = 1.82/1.07
T0.13 = 1.7
Or T = 59.25 min
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Community Answer
Directions: The work-tool system is governed by the following equation...
Effect on Tool Life for a 20% Increase in Cutting Speed:
Given:
Initial cutting speed (V) = 25 m/min
Increase in cutting speed = 20%
To calculate the effect on tool life, we need to substitute the new cutting speed into the equation and compare it with the initial tool life.
New cutting speed = 25 m/min + 20% of 25 m/min = 25 m/min + (20/100) * 25 m/min = 25 m/min + 5 m/min = 30 m/min
Substituting the values into the equation:
26.035 = (30)^0.13 * (0.3125)^0.77 * (2.50)^0.37
This equation gives us the new tool life. Let's calculate it.
New Tool Life = 26.035 / [(30)^0.13 * (0.3125)^0.77 * (2.50)^0.37]
Effect on Tool Life for a 20% Increase in Cutting Speed = Initial Tool Life - New Tool Life
Effect on Tool Life for a 20% Increase in Cutting Speed = 100 min - (calculated new tool life)
Effect on Tool Life for a 20% Increase in Cutting Speed = 100 min - (calculated new tool life)
Effect on Tool Life for a 20% Increase in Cutting Speed = 100 - X (where X is the calculated new tool life)
Effect on Tool Life for a 20% Increase in Cutting Speed = X min (approximately)
Effect on Tool Life for a 20% Increase in Feed:
Given:
Initial feed (f) = 0.3125 mm/rev
Increase in feed = 20%
To calculate the effect on tool life, we need to substitute the new feed into the equation and compare it with the initial tool life.
New feed = 0.3125 mm/rev + 20% of 0.3125 mm/rev = 0.3125 mm/rev + (20/100) * 0.3125 mm/rev = 0.3125 mm/rev + 0.0625 mm/rev = 0.375 mm/rev
Substituting the values into the equation:
26.035 = (25)^0.13 * (0.375)^0.77 * (2.50)^0.37
This equation gives us the new tool life. Let's calculate it.
New Tool Life = 26.035 / [(25)^0.13 * (0.375)^0.77 * (2.50)^0.37]
Effect on Tool Life for a 20% Increase in Feed = Initial Tool Life - New Tool Life
Effect on Tool Life for a 20% Increase in Feed = 100 min - (calculated new tool life)
Effect on Tool Life for a 20% Increase in Feed = 100 - Y (where Y is the calculated new tool life)
Effect on Tool Life for a 20% Increase in Feed = Y min (approximately)
Effect on Tool Life for a 20% Increase in Depth of Cut:
Given:
Initial depth of cut (d) = 2.50 mm
Increase in depth of cut = 20%
To calculate the effect on tool life, we need to substitute the new depth of cut into the equation and compare it with the
Given:
Initial cutting speed (V) = 25 m/min
Increase in cutting speed = 20%
To calculate the effect on tool life, we need to substitute the new cutting speed into the equation and compare it with the initial tool life.
New cutting speed = 25 m/min + 20% of 25 m/min = 25 m/min + (20/100) * 25 m/min = 25 m/min + 5 m/min = 30 m/min
Substituting the values into the equation:
26.035 = (30)^0.13 * (0.3125)^0.77 * (2.50)^0.37
This equation gives us the new tool life. Let's calculate it.
New Tool Life = 26.035 / [(30)^0.13 * (0.3125)^0.77 * (2.50)^0.37]
Effect on Tool Life for a 20% Increase in Cutting Speed = Initial Tool Life - New Tool Life
Effect on Tool Life for a 20% Increase in Cutting Speed = 100 min - (calculated new tool life)
Effect on Tool Life for a 20% Increase in Cutting Speed = 100 min - (calculated new tool life)
Effect on Tool Life for a 20% Increase in Cutting Speed = 100 - X (where X is the calculated new tool life)
Effect on Tool Life for a 20% Increase in Cutting Speed = X min (approximately)
Effect on Tool Life for a 20% Increase in Feed:
Given:
Initial feed (f) = 0.3125 mm/rev
Increase in feed = 20%
To calculate the effect on tool life, we need to substitute the new feed into the equation and compare it with the initial tool life.
New feed = 0.3125 mm/rev + 20% of 0.3125 mm/rev = 0.3125 mm/rev + (20/100) * 0.3125 mm/rev = 0.3125 mm/rev + 0.0625 mm/rev = 0.375 mm/rev
Substituting the values into the equation:
26.035 = (25)^0.13 * (0.375)^0.77 * (2.50)^0.37
This equation gives us the new tool life. Let's calculate it.
New Tool Life = 26.035 / [(25)^0.13 * (0.375)^0.77 * (2.50)^0.37]
Effect on Tool Life for a 20% Increase in Feed = Initial Tool Life - New Tool Life
Effect on Tool Life for a 20% Increase in Feed = 100 min - (calculated new tool life)
Effect on Tool Life for a 20% Increase in Feed = 100 - Y (where Y is the calculated new tool life)
Effect on Tool Life for a 20% Increase in Feed = Y min (approximately)
Effect on Tool Life for a 20% Increase in Depth of Cut:
Given:
Initial depth of cut (d) = 2.50 mm
Increase in depth of cut = 20%
To calculate the effect on tool life, we need to substitute the new depth of cut into the equation and compare it with the
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Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer?
Question Description
Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer?.
Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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Here you can find the meaning of Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Directions: The work-tool system is governed by the following equation, when machining steel with H.S.S. cutting tools.26.035 = VT0.13f 0.77d0.37A 100 min. tool life was obtained under the following cutting conditions:Velocity = 25 m/minFeed = 0.3125 mm/revDiameter of bar = 2.50 mmQ. What is the effect on the tool life respectively, for a 20% increase in the cutting speed, feed and depth of cut, taking each separately?a)25 min, 59.25 min, 34.23 minb)34.23 min, 25 min, 59.25 minc)25 min, 34.23 min, 59.25 mind)59.25 min, 34.23 min, 25 minCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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