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Given below are two cleavage reactions:
(i) (CH3)3COCH3 → CH3I + (CH3)3COH
(ii) (CH3)3COCH3 → CH3OH + (CH3)3CI
- a)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.
- b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.
- c)The reagent used in both reactions (i) and (ii) is concentrated HI.
- d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.
Correct answer is option 'A'. Can you explain this answer?
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Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)...
Reagent used in reaction (i) and (ii):
- The reagent used in reaction (i) is anhydrous HI in ether.
- The reagent used in reaction (ii) is concentrated HI.
Explanation:
In reaction (i), the cleavage of the carbon-oxygen bond occurs, resulting in the formation of CH3I and (CH3)3COH. This reaction is known as the iodoform reaction. The reagent used is anhydrous HI in ether. Anhydrous HI refers to hydrogen iodide without any water content, and it is dissolved in ether as a solvent.
In reaction (ii), the cleavage of the carbon-oxygen bond also occurs, but the products formed are CH3OH and (CH3)3CI. This reaction is also a form of cleavage reaction known as the dealkylation reaction. The reagent used is concentrated HI. Concentrated HI refers to hydrogen iodide in a concentrated form, typically in water.
The difference in the reagents used in these reactions is due to the different reaction conditions required for each reaction. Anhydrous HI in ether is used in reaction (i) because the iodoform reaction is facilitated by the presence of anhydrous conditions and an organic solvent like ether. On the other hand, concentrated HI is used in reaction (ii) because the dealkylation reaction can occur under aqueous conditions.
Hence, the correct answer is option A, which states that the reagent used in reaction (i) is anhydrous HI in ether and the reagent used in reaction (ii) is concentrated HI.
- The reagent used in reaction (i) is anhydrous HI in ether.
- The reagent used in reaction (ii) is concentrated HI.
Explanation:
In reaction (i), the cleavage of the carbon-oxygen bond occurs, resulting in the formation of CH3I and (CH3)3COH. This reaction is known as the iodoform reaction. The reagent used is anhydrous HI in ether. Anhydrous HI refers to hydrogen iodide without any water content, and it is dissolved in ether as a solvent.
In reaction (ii), the cleavage of the carbon-oxygen bond also occurs, but the products formed are CH3OH and (CH3)3CI. This reaction is also a form of cleavage reaction known as the dealkylation reaction. The reagent used is concentrated HI. Concentrated HI refers to hydrogen iodide in a concentrated form, typically in water.
The difference in the reagents used in these reactions is due to the different reaction conditions required for each reaction. Anhydrous HI in ether is used in reaction (i) because the iodoform reaction is facilitated by the presence of anhydrous conditions and an organic solvent like ether. On the other hand, concentrated HI is used in reaction (ii) because the dealkylation reaction can occur under aqueous conditions.
Hence, the correct answer is option A, which states that the reagent used in reaction (i) is anhydrous HI in ether and the reagent used in reaction (ii) is concentrated HI.
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Community Answer
Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)...
The low polarity of solvent ether favours the SN2 mechanism.
The O-CH3 bond breaks and methyl iodide and tertiary butyl alcohol are formed as products.
The presence of a solvent with high polarity such as water favours the SN1 mechanism.
The (CH3)3-O bond breaks and methyl alcohol is formed.
The mechanism is
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Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)3COH(ii) (CH3)3COCH3 → CH3OH + (CH3)3CIa)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.c)The reagent used in both reactions (i) and (ii) is concentrated HI.d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.Correct answer is option 'A'. Can you explain this answer?
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Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)3COH(ii) (CH3)3COCH3 → CH3OH + (CH3)3CIa)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.c)The reagent used in both reactions (i) and (ii) is concentrated HI.d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)3COH(ii) (CH3)3COCH3 → CH3OH + (CH3)3CIa)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.c)The reagent used in both reactions (i) and (ii) is concentrated HI.d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)3COH(ii) (CH3)3COCH3 → CH3OH + (CH3)3CIa)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.c)The reagent used in both reactions (i) and (ii) is concentrated HI.d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.Correct answer is option 'A'. Can you explain this answer?.
Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)3COH(ii) (CH3)3COCH3 → CH3OH + (CH3)3CIa)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.c)The reagent used in both reactions (i) and (ii) is concentrated HI.d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)3COH(ii) (CH3)3COCH3 → CH3OH + (CH3)3CIa)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.c)The reagent used in both reactions (i) and (ii) is concentrated HI.d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)3COH(ii) (CH3)3COCH3 → CH3OH + (CH3)3CIa)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.c)The reagent used in both reactions (i) and (ii) is concentrated HI.d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.Correct answer is option 'A'. Can you explain this answer?.
Solutions for Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)3COH(ii) (CH3)3COCH3 → CH3OH + (CH3)3CIa)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.c)The reagent used in both reactions (i) and (ii) is concentrated HI.d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)3COH(ii) (CH3)3COCH3 → CH3OH + (CH3)3CIa)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.c)The reagent used in both reactions (i) and (ii) is concentrated HI.d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)3COH(ii) (CH3)3COCH3 → CH3OH + (CH3)3CIa)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.c)The reagent used in both reactions (i) and (ii) is concentrated HI.d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)3COH(ii) (CH3)3COCH3 → CH3OH + (CH3)3CIa)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.c)The reagent used in both reactions (i) and (ii) is concentrated HI.d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Given below are two cleavage reactions:(i) (CH3)3COCH3 → CH3I + (CH3)3COH(ii) (CH3)3COCH3 → CH3OH + (CH3)3CIa)The reagent used in reaction (i) is anhydrous HI in ether and that in reaction (ii) is concentrated HI.b)The reagent used in reaction (i) is concentrated HI and that in reaction (ii) is anhydrous HI in ether.c)The reagent used in both reactions (i) and (ii) is concentrated HI.d)The reagent used in both reactions (i) and (ii) is anhydrous HI in ether.Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
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