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Let the eccentricity of the hyperbola be the reciprocal of that of the ellipse x2 + 4y2 = 4. Also, the hyperbola passes through a focus of the ellipse. Then, the equation of the hyperbola isa)x2 - 3y2 = 3b)x2 - 3y2 = 1c)3x2 - y2 = 3d)3x2 - y2 = 1Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let the eccentricity of the hyperbola be the reciprocal of that of the ellipse x2 + 4y2 = 4. Also, the hyperbola passes through a focus of the ellipse. Then, the equation of the hyperbola isa)x2 - 3y2 = 3b)x2 - 3y2 = 1c)3x2 - y2 = 3d)3x2 - y2 = 1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let the eccentricity of the hyperbola be the reciprocal of that of the ellipse x2 + 4y2 = 4. Also, the hyperbola passes through a focus of the ellipse. Then, the equation of the hyperbola isa)x2 - 3y2 = 3b)x2 - 3y2 = 1c)3x2 - y2 = 3d)3x2 - y2 = 1Correct answer is option 'A'. Can you explain this answer?.

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Here you can find the meaning of Let the eccentricity of the hyperbola be the reciprocal of that of the ellipse x2 + 4y2 = 4. Also, the hyperbola passes through a focus of the ellipse. Then, the equation of the hyperbola isa)x2 - 3y2 = 3b)x2 - 3y2 = 1c)3x2 - y2 = 3d)3x2 - y2 = 1Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Let the eccentricity of the hyperbola be the reciprocal of that of the ellipse x2 + 4y2 = 4. Also, the hyperbola passes through a focus of the ellipse. Then, the equation of the hyperbola isa)x2 - 3y2 = 3b)x2 - 3y2 = 1c)3x2 - y2 = 3d)3x2 - y2 = 1Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Let the eccentricity of the hyperbola be the reciprocal of that of the ellipse x2 + 4y2 = 4. Also, the hyperbola passes through a focus of the ellipse. Then, the equation of the hyperbola isa)x2 - 3y2 = 3b)x2 - 3y2 = 1c)3x2 - y2 = 3d)3x2 - y2 = 1Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Let the eccentricity of the hyperbola be the reciprocal of that of the ellipse x2 + 4y2 = 4. Also, the hyperbola passes through a focus of the ellipse. Then, the equation of the hyperbola isa)x2 - 3y2 = 3b)x2 - 3y2 = 1c)3x2 - y2 = 3d)3x2 - y2 = 1Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Let the eccentricity of the hyperbola be the reciprocal of that of the ellipse x2 + 4y2 = 4. Also, the hyperbola passes through a focus of the ellipse. Then, the equation of the hyperbola isa)x2 - 3y2 = 3b)x2 - 3y2 = 1c)3x2 - y2 = 3d)3x2 - y2 = 1Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.