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Ripple factor of a full-wave rectifier without filter will be
- a)0.48
- b)0.20
- c)1.21
- d)0.24
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Ripple factor of a full-wave rectifier without filter will bea)0.48b)0...
Explanation:
Ripple factor is a measure of the amount of AC component present in the rectified output of a power supply. Ripple is caused by the fact that the rectifier capacitor cannot smooth the output completely.
Full-wave rectifier without filter:
In a full-wave rectifier, both halves of the input waveform are used to produce a pulsating DC output. The output voltage of a full-wave rectifier without a filter is shown below:
The waveform has a ripple component that is superimposed on the DC component. The ripple is caused by the fact that the rectifier capacitor charges to the peak voltage of the input waveform and discharges through the load resistance.
Ripple factor formula:
The ripple factor is defined as the ratio of the RMS value of the ripple voltage to the DC output voltage. The formula for the ripple factor is given by:
Ripple factor = (Vrms of ripple voltage) / (DC output voltage)
In a full-wave rectifier without filter, the RMS value of the ripple voltage can be calculated as:
Vrms = Vp / 2√2
Where Vp is the peak-to-peak value of the ripple voltage.
DC output voltage can be calculated as:
Vdc = Vp / π
Therefore, the ripple factor for a full-wave rectifier without filter can be calculated as:
Ripple factor = (Vrms of ripple voltage) / (DC output voltage)
= (Vp / 2√2) / (Vp / π)
= π / (2√2)
= 0.48
Therefore, the correct answer is option 'A'.
Ripple factor is a measure of the amount of AC component present in the rectified output of a power supply. Ripple is caused by the fact that the rectifier capacitor cannot smooth the output completely.
Full-wave rectifier without filter:
In a full-wave rectifier, both halves of the input waveform are used to produce a pulsating DC output. The output voltage of a full-wave rectifier without a filter is shown below:
The waveform has a ripple component that is superimposed on the DC component. The ripple is caused by the fact that the rectifier capacitor charges to the peak voltage of the input waveform and discharges through the load resistance.
Ripple factor formula:
The ripple factor is defined as the ratio of the RMS value of the ripple voltage to the DC output voltage. The formula for the ripple factor is given by:
Ripple factor = (Vrms of ripple voltage) / (DC output voltage)
In a full-wave rectifier without filter, the RMS value of the ripple voltage can be calculated as:
Vrms = Vp / 2√2
Where Vp is the peak-to-peak value of the ripple voltage.
DC output voltage can be calculated as:
Vdc = Vp / π
Therefore, the ripple factor for a full-wave rectifier without filter can be calculated as:
Ripple factor = (Vrms of ripple voltage) / (DC output voltage)
= (Vp / 2√2) / (Vp / π)
= π / (2√2)
= 0.48
Therefore, the correct answer is option 'A'.
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Ripple factor of a full-wave rectifier without filter will bea)0.48b)0.20c)1.21d)0.24Correct answer is option 'A'. Can you explain this answer?
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